我想使用jetty启动我的应用程序,所以我添加了下面提到的依赖项。当我运行主方法时,Jetty成功启动。(我正在做一个struts2+spring3+hibernate maven项目,我也可以在tomcat中部署它)
现在我想从战争包装pom创建一个可执行的jar。因此,我在pom中添加了maven汇编插件。(我尝试了maven jar插件,但它没有添加依赖项)
来源
插件
<build>
<plugins>
<plugin>
<artifactId>maven-war-plugin</artifactId>
<version>2.3</version>
<configuration>
<archive>
<manifest>
<mainClass>com.dca.engine.StartDCA</mainClass>
</manifest>
</archive>
<packagingExcludes>WEB-INF/lib/jetty*.jar,WEB-INF/lib/org.apache.taglibs.standard.glassfish*.jar,WEB-INF/lib/org.apache.jasper.glassfish*.jar,WEB-INF/lib/org.eclipse.jdt.core*.jar,WEB-INF/lib/javax.servlet.jsp*.jar,WEB-INF/lib/javax.el*.jar</packagingExcludes>
<escapeString></escapeString>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.4</version>
<configuration>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<archive>
<manifest>
<mainClass>com.dca.engine.StartDCA</mainClass>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
<resources>
<resource>
<directory>src/main/java</directory>
<includes>
<include>**/*.java</include>
<include>**/*.xml</include>
</includes>
</resource>
<resource>
<directory>src/main/resources</directory>
<filtering>true</filtering>
</resource>
</resources>
</build>
嵌入式码头
<dependency>
<groupId>org.eclipse.jetty</groupId>
<artifactId>jetty-server</artifactId>
<version>8.1.10.v20130312</version>
</dependency>
<dependency>
<groupId>org.eclipse.jetty</groupId>
<artifactId>jetty-webapp</artifactId>
<version>8.1.10.v20130312</version>
<!-- <scope>provided</scope> -->
</dependency>
<dependency>
<groupId>org.eclipse.jetty</groupId>
<artifactId>jetty-jsp</artifactId>
<version>8.1.10.v20130312</version>
<!-- <scope>provided</scope> -->
</dependency>
主要方法
Server server = new Server(8080);
System.setProperty("is_DCA", "YES");
WebAppContext webAppContext = new WebAppContext();
webAppContext.setResourceBase("/home/myfolder/workspace/app/dca/src/main/webapp");
webAppContext.setDescriptor("/home/myfolder/workspace/app/dca/src/main/webapp/WEB-INF/web.xml");
webAppContext.setContextPath("/app");
server.setHandler(webAppContext);
server.start();
server.join();
启动应用程序
我用java-jar/home/myfolder/workspace/app/dca/target/app-dca-1.0-jar-with-dependences.jar 运行创建的jar
码头启动异常。
INFO 10-12 15:03:01,609 - jetty-8.y.z-SNAPSHOT
INFO 10-12 15:03:01,776 - Initializing Spring root WebApplicationContext
INFO 10-12 15:03:01,776 - Root WebApplicationContext: initialization started
INFO 10-12 15:03:01,843 - Refreshing Root WebApplicationContext: startup date [Tue Dec 10 15:03:01 IST 2013]; root of context hierarchy
INFO 10-12 15:03:01,885 - Loading XML bean definitions from class path resource [applicationContext-dca.xml]
ERROR 10-12 15:03:05,725 - Context initialization failed
org.springframework.beans.factory.parsing.BeanDefinitionParsingException: Configuration problem: Unable to locate Spring NamespaceHandler for XML schema namespace [http://www.springframework.org/schema/util]
Offending resource: class path resource [applicationContext-dca.xml]
at org.springframework.beans.factory.parsing.FailFastProblemReporter.error(FailFastProblemReporter.java:68)
at org.springframework.beans.factory.parsing.ReaderContext.error(ReaderContext.java:85)
at org.springframework.beans.factory.parsing.ReaderContext.error(ReaderContext.java:80)
at org.springframework.beans.factory.xml.BeanDefinitionParserDelegate.error(BeanDefinitionParserDelegate.java:316)
at org.springframework.beans.factory.xml.BeanDefinitionParserDelegate.parseCustomElement(BeanDefinitionParserDelegate.java:1420)
at org.springframework.beans.factory.xml.BeanDefinitionParserDelegate.parseCustomElement(BeanDefinitionParserDelegate.java:1413)
at org.springframework.beans.factory.xml.DefaultBeanDefinitionDocumentReader.parseBeanDefinitions(DefaultBeanDefinitionDocumentReader.java:184)
at org.springframework.beans.factory.xml.DefaultBeanDefinitionDocumentReader.doRegisterBeanDefinitions(DefaultBeanDefinitionDocumentReader.java:140)
at org.springframework.beans.factory.xml.DefaultBeanDefinitionDocumentReader.registerBeanDefinitions(DefaultBeanDefinitionDocumentReader.java:111)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.registerBeanDefinitions(XmlBeanDefinitionReader.java:493)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions(XmlBeanDefinitionReader.java:390)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:334)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:302)
at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:174)
at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:209)
有没有一种可能的方法,我可以使用战争创造的码头。它在/WEB-INF/lib/文件夹中有jar,所有属性文件和xml文件都在/WEB-INF/lib/中,我尝试运行war
java-jar/home/myfolder/workspace/app/dca/target/app-dca-1.0.war
但它无法定位主类。
在创建可执行的战争检查sumit的答案时工作
我得到了这个问题的例外。当我将jetty版本替换为7.6.7.v20120910时,它起到了的作用
我不知道为什么它不适用于jetty 8.1.10.v20130312
如果您不想使用Jetty,而是对使用Tomcat持开放态度,那么以下操作将非常有效:
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
<version>2.0</version>
<executions>
<execution>
<id>tomcat-run</id>
<goals>
<goal>exec-war-only</goal>
</goals>
<phase>package</phase>
<configuration>
<path>/standalone</path>
<enableNaming>false</enableNaming>
<finalName>standalone.jar</finalName>
<charset>utf-8</charset>
</configuration>
</execution>
</executions>
</plugin>
这将创建一个名为"standalone.jar"的uberjar,然后只需调用即可运行它
java -jar standalone.jar
这将在上启动应用程序http://localhost:8080/standalone
选择备用端口很容易
java -jar standalone.jar -httpPort=7070
感谢Tomasz Nurkiewicz的博客文章强调了这一点http://www.nurkiewicz.com/2012/11/standalone-web-application-with.html
您可以使用maven shade插件创建一个可执行的JAR文件,而不是像公认的答案那样对WAR文件的内容进行黑客攻击。这具有以下优点:
- 该插件包含用于合并META-INF/services、LICENSE和README文件内容的"转换器"
- 您最终得到一个JAR文件。WAR文件并没有被设计成可执行的(尽管它是有效的)
- 通过将所有依赖项拆包到同一个JAR文件中,您将被迫删除重复的类,并使内容更难进行反向工程
看看http://uguptablog.blogspot.com/2012/09/embedded-jetty-executable-war-with.html
相关代码为
ProtectionDomain domain = Main.class.getProtectionDomain();
URL location = domain.getCodeSource().getLocation();
WebAppContext webapp = new WebAppContext();
webapp.setContextPath("/");
webapp.setWar(location.toExternalForm());
server.setHandler(webapp);
希望能有所帮助。
我知道(但从未尝试过)最简单的方法是winstone maven插件,就像Jenkins CI所做的那样(多么好的例子:D)。它不使用Jetty(甚至我喜欢这个工具:D),而是使用Winstone。
Maven插件使用情况
<plugin>
<groupId>net.sf.alchim</groupId>
<artifactId>winstone-maven-plugin</artifactId>
<executions>
<execution>
<goals>
<goal>embed</goal>
</goals>
<phase>package</phase>
</execution>
</executions>
</plugin>
很容易,不是吗?:)它将生成一个可执行的独立jar:app-dca-1.0-standalone.jar
文件
- Winstone Servlet容器:http://winstone.sourceforge.net/
- Winstone Maven插件:http://alchim.sourceforge.net/winstone-maven-plugin/usage.html
- 完整示例:http://www.jayway.com/2008/11/28/executable-war-with-winstone-maven-plugin/