我正试图在本地OSX 10.11中启动QLocalServer。
我有一个客户端,它尝试循环连接到服务器:
int connect(const char* filename) {
int sock;
struct sockaddr_un serv_addr;
memset(&serv_addr, 0x00, sizeof(serv_addr));
serv_addr.sun_family = AF_LOCAL;
strncpy(serv_addr.sun_path, filename, sizeof(serv_addr.sun_path) - 1);
if ((sock = socket(AF_UNIX, SOCK_STREAM, 0)) == -1) {
return sock;
}
if (connect(sock, (struct sockaddr *)&serv_addr, sizeof(serv_addr)) == -1) {
close(sock);
sock = -1;
return sock;
}
return sock;
}
int main() {
int sock;
while((sock = connect("my_socket_server")) == -1) {
usleep(3000);
}
// The code never reaches this line
const char* buffer = "hello";
if (send(sock, buffer, strlen(buffer), 0) < 0) {
exit(1);
}
return 0;
}
当这段代码运行时,我尝试在另一个应用程序中启动QLocalServer:
// Starting server:
QString socket_path = "my_socket_server";
QLocalServer::removeServer(socket_path);
if (!server.listen(socket_path)) {
return false;
}
connect(&server, &QLocalServer::newConnection, this, &MyServerClass::newConnection);
...
void MyServerClass::newConnection() {
socket = server.nextPendingConnection(); // socket - member of MyServerClass
connect(socket, &QLocalSocket::disconnected, socket, &QLocalSocket::deleteLater);
connect(socket, &QLocalSocket::readyRead, this, &MyServerClass::readyRead);
}
...
void MyServerClass::readyRead() {
if (!socket->bytesAvailable()) {
exit(1); // THIS CODE WAS CALLED. WHY?
}
...
}
为什么在调用readyRead时,字节不可用?
您可能得到多个连接,在这种情况下,socket
变量可能指向与发出readyRead
信号的对象不同的对象。使用QObject::sender
在插槽中获取正确的对象,或者使用QSignalMapper
。如果使用Qt5,还可以使用lambda函数并捕获socket
对象。