我想比较两个句子(句子A和B),这样程序就会从句子A输出对句子B所做的更改。例如:
句子 A:It's a lovely day today.
句子B:It's a very lovely day today, isnt it?
输出:It's a [I:very] lovely day today [C:./,] [I:isnt it?]
哪里:
I
= 插入,
C
= 已更改
PS:我还没有开始编码,因为我想收集你关于如何最好地实现这个案例的一些想法。
我想出了下面的代码和这个问题。
未考虑的条件
- 从任何列表中删除的项目
- 第一个字符差异
- 差异项的重复
如果您有疑问,请检查并告诉我。
public static void main(String[] args) {
String str1 = "It's a lovely day today.";
String str2 = "It's a very lovely day today, isnt it?";
StringBuilder builder = new StringBuilder();
StringBuilder added = new StringBuilder();
StringBuilder changed = new StringBuilder();
for (int i = 0; i < str1.length(); i++)
for (int j = 0; j < str2.length(); j++) {
if (str1.charAt(i) == str2.charAt(j)) {
if (added.length() > 0) {
builder.append("[I:" + added.toString() + "]");
added = new StringBuilder();
}
if (changed.length() > 0) {
changed.append("[C:" + changed.toString() + "]");
changed = new StringBuilder();
}
// skip as there is no difference.
builder.append(str1.charAt(i));
i++;
// check if index -1 chars are equal then there is
// difference start
} else if (str1.charAt(i - 1) == str2.charAt(j - 1)) {
// check if end of line
if ((i + 1 == str1.length())
|| (str1.charAt(i + 1) == str2.charAt(j + 1))) {
changed.append(str1.charAt(i));
changed.append("/");
changed.append(str2.charAt(j));
j++;
// everything is added
if (i + 1 == str1.length()) {
while (j < str2.length() - 1)
added.append(str2.charAt(j++));
}
continue;
}
// Go until next equal found
while (!(str1.charAt(i) == str2.charAt(j))
&& j < str2.length() - 1) {
added.append(str2.charAt(j++));
}
j--;
}
}
if (changed.length() > 0) {
builder.append("[C:" + changed.toString() + "]");
}
if (added.length() > 0) {
builder.append("[I:" + added.toString() + "]");
}
System.out.println(builder.toString());
}
输出
It's a [I:very ]lovely day today[C:./,][I: isnt it]