CSS ~ 选择器不会将样式应用于所有目标元素(Z 索引到下一个/上一个标签)

Question

我有以下纯 css 幻灯片，除了缩略图之外，我正在尝试实现"下一个/上一个"按钮(两者都是指向<input type="radio">的标签)。

缩略图是带有图像的标签，因此我为按钮创建了更多标签。问题是我无法弄清楚如何正确隐藏它们，除了检查输入旁边的那些。

我尝试了以下代码：

.slider input[name='slide_switch'] ~ label.next,
.slider input[name='slide_switch'] ~ label.previous
{
z-index: -1
}
.slider input[name='slide_switch']:checked ~ label.next,
.slider input[name='slide_switch']:checked ~ label.previous {
z-index: 1
}

这应该针对 HTML 中的所有<label class="next">和<label class="previous">，但由于某种原因它不起作用，我"可以看到"多个按钮，一个接一个，因为我给了它们opacity: 0.6并且它们看起来不是半透明的。但是，它们中的最后两个显示正确的不透明度并且正在工作，如果我在最后一张图片中，我可以单击上一个按钮，它会将我带到第 4 张图片，如果我单击下一步它会将我带到第 5 张图片(不幸的是，所有图片都会发生这种情况)。

我在这里工作：https://jsfiddle.net/5v6ajfup/

该 HTML 代码：

<div class="slider">
<input type="radio" name="slide_switch" id="id1"/>
<label class="thumbnail" for="id1">
<img src="http://thecodeplayer.com/uploads/media/3yiC6Yq.jpg" width="100"/>
</label>
<img src="http://thecodeplayer.com/uploads/media/3yiC6Yq.jpg"/>
<label class="next" for="id2">></label>
<input type="radio" name="slide_switch" id="id2" checked="checked"/>
<label class="thumbnail" for="id2">
<img src="http://thecodeplayer.com/uploads/media/40Ly3VB.jpg" width="100"/>
</label>
<img src="http://thecodeplayer.com/uploads/media/40Ly3VB.jpg"/>
<label class="previous" for="id1">></label>
<label class="next" for="id3">></label>
<input type="radio" name="slide_switch" id="id3"/>
<label class="thumbnail" for="id3">
<img src="http://thecodeplayer.com/uploads/media/00kih8g.jpg" width="100"/>
</label>
<img src="http://thecodeplayer.com/uploads/media/00kih8g.jpg"/>
<label class="previous" for="id2">></label>
<label class="next" for="id4">></label>
<input type="radio" name="slide_switch" id="id4"/>
<label class="thumbnail" for="id4">
<img src="http://thecodeplayer.com/uploads/media/2rT2vdx.jpg" width="100"/>
</label>
<img src="http://thecodeplayer.com/uploads/media/2rT2vdx.jpg"/>
<label class="next" for="id5">></label>
<label class="previous" for="id3">></label>
<input type="radio" name="slide_switch" id="id5"/>
<label class="thumbnail" for="id5">
<img src="http://thecodeplayer.com/uploads/media/8k3N3EL.jpg" width="100"/>
</label>
<img src="http://thecodeplayer.com/uploads/media/8k3N3EL.jpg"/>
<label class="previous" for="id4">></label>
</div>

CSS代码：

* { margin: 0; padding: 0 }
body { background: #ccc }
.slider {
width: 640px;
position: relative;
padding-top: 320px;
margin: 20px auto;
box-shadow: 0 10px 20px -5px rgba(0, 0, 0, 0.75);
}
.slider > img {
position: absolute;
left: 0; top: 0;
transition: all 0.5s;
display: block
}
.slider input[name='slide_switch'] {
display: none;
}
.slider label.next, .slider label.previous {
position: absolute;
left: 0; top: 0;
display: block;
font-size:3em;
opacity: 0.6;
cursor: pointer;
color: white;
}
.slider label.next { left: 560px; line-height: 320px }
.slider label.previous { left: 50px; line-height: 320px; transform: rotateY(180deg) }
.slider label.thumbnail {
margin: 18px 0 0 18px;
border: 3px solid #999;
float: left;
cursor: pointer;
transition: all 0.5s;
opacity: 0.6;
}
.slider label.thumbnail:hover { opacity: 0.8 }
.slider label.thumbnail img {
display: block;
}
.slider input[name='slide_switch']:checked + label.thumbnail {
border-color: #666;
opacity: 1;
}
.slider input[name='slide_switch'] ~ label.next,
.slider input[name='slide_switch'] ~ label.previous
{
z-index: -1
}
.slider input[name='slide_switch']:checked ~ label.next,
.slider input[name='slide_switch']:checked ~ label.previous {
z-index: 1
}
.slider input[name='slide_switch'] ~ img {
opacity: 0;
transform: scale(1.1);
}
.slider input[name='slide_switch']:checked + label.thumbnail + img {
opacity: 1;
transform: scale(1);
}

(来源)

Answer 1

此规则

.slider input[name='slide_switch']:checked ~ label.next,
.slider input[name='slide_switch']:checked ~ label.previous {
z-index: 1
}

将针对input[name='slide_switch']后出现的所有label.next/label.previous，而不仅仅是直接的input[name='slide_switch']。

您需要使用每个input[name='slide_switch']特定标签的for属性来定位这些标签，也可以使用nth-of-type

---

根据评论更新

解决方案 1 - 首选

不要更改上面的:checked规则，而是将每组input/image/thumb/arrow包装在一个div中，并将此规则的.slider > img选择器更改为slider > div > img

更新的小提琴

堆栈代码段

* { margin: 0; padding: 0 }
body { background: #ccc }
.slider {
	width: 640px;
	position: relative;
	padding-top: 320px;
	margin: 20px auto;
	box-shadow: 0 10px 20px -5px rgba(0, 0, 0, 0.75);
}
.slider > div > img {
	position: absolute;
	left: 0; top: 0;
	transition: all 0.5s;
display: block
}
.slider input[name='slide_switch'] {
	display: none;
}
.slider label.next, .slider label.previous {
	position: absolute;
	left: 0; top: 0;
display: block;
font-size:3em;
	opacity: 0.6;
	cursor: pointer;
color: white;
}
.slider label.next { left: 560px; line-height: 320px }
.slider label.previous { left: 50px; line-height: 320px; transform: rotateY(180deg) }
.slider label.thumbnail {
	margin: 18px 0 0 18px;
	border: 3px solid #999;
	float: left;
	cursor: pointer;
	transition: all 0.5s;
	opacity: 0.6;
}
.slider label.thumbnail:hover { opacity: 0.8 }
.slider label.thumbnail img {
	display: block;
}
.slider input[name='slide_switch']:checked + label.thumbnail {
	border-color: #666;
	opacity: 1;
}
.slider input[name='slide_switch'] ~ label.next,
.slider input[name='slide_switch'] ~ label.previous
{
	z-index: -1
}
.slider input[name='slide_switch']:checked ~ label.next,
.slider input[name='slide_switch']:checked ~ label.previous {
	z-index: 1
}
.slider input[name='slide_switch'] ~ img {
	opacity: 0;
	transform: scale(1.1);
}
.slider input[name='slide_switch']:checked + label.thumbnail + img {
	opacity: 1;
	transform: scale(1);
}

<div class="slider">
<div>
<input type="radio" name="slide_switch" id="id1" />
<label class="thumbnail" for="id1">
<img src="http://thecodeplayer.com/uploads/media/3yiC6Yq.jpg" width="100" />
</label>
<img src="http://thecodeplayer.com/uploads/media/3yiC6Yq.jpg" />
<label class="next" for="id2">></label>
</div>
<div>
<input type="radio" name="slide_switch" id="id2" checked/>
<label class="thumbnail" for="id2">
<img src="http://thecodeplayer.com/uploads/media/40Ly3VB.jpg" width="100" />
</label>
<img src="http://thecodeplayer.com/uploads/media/40Ly3VB.jpg" />
<label class="previous" for="id1">></label>
<label class="next" for="id3">></label>
</div>
<div>
<input type="radio" name="slide_switch" id="id3" />
<label class="thumbnail" for="id3">
<img src="http://thecodeplayer.com/uploads/media/00kih8g.jpg" width="100" />
</label>
<img src="http://thecodeplayer.com/uploads/media/00kih8g.jpg" />
<label class="previous" for="id2">></label>
<label class="next" for="id4">></label>
</div>
<div>
<input type="radio" name="slide_switch" id="id4" />
<label class="thumbnail" for="id4">
<img src="http://thecodeplayer.com/uploads/media/2rT2vdx.jpg" width="100" />
</label>
<img src="http://thecodeplayer.com/uploads/media/2rT2vdx.jpg" />
<label class="next" for="id5">></label>
<label class="previous" for="id3">></label>
</div>
<div>
<input type="radio" name="slide_switch" id="id5" />
<label class="thumbnail" for="id5">
<img src="http://thecodeplayer.com/uploads/media/8k3N3EL.jpg" width="100" />
</label>
<img src="http://thecodeplayer.com/uploads/media/8k3N3EL.jpg" />
<label class="previous" for="id4">></label>
</div>
</div>

---

解决方案 2

替换此规则

.slider input[name='slide_switch']:checked ~ label.next,
.slider input[name='slide_switch']:checked ~ label.previous {
z-index: 1
}

有了这个

.slider input#id1:checked ~ label[for="id2"],
.slider input#id2:checked ~ label[for="id1"],
.slider input#id2:checked ~ label[for="id3"],
.slider input#id3:checked ~ label[for="id2"],
.slider input#id3:checked ~ label[for="id4"],
.slider input#id4:checked ~ label[for="id3"],
.slider input#id4:checked ~ label[for="id5"],
.slider input#id5:checked ~ label[for="id4"]
{
z-index: 1;
}

Answer 2

您没有正确使用波浪号选择器。 波浪号左手之后的所有同级元素实际上都将匹配。

https://stackoverflow.com/questions/10782054/what-does-the-tilde-squiggle-twiddle-css-selector-mean

因此，即使您的代码将 z-index 设置为 -1，在大多数情况下也会被以下内容覆盖(因为此规则更具体)：

.slider input[name='slide_switch']:checked ~ label.next,
.slider input[name='slide_switch']:checked ~ label.previous {
z-index: 1;
}