>我正在做以下程序,我在其中创建各种过程,就像它们是二叉树一样,我希望"左边"的孩子做与"右边"的孩子不同的事情,但它输出我右边的 2 个孩子或左边的 2 个孩子,我不想这样。
void slice(int dir){
if (dir == 1) {
printf("izq ");
printf("child pid %d parent pid %dn",getpid(),getppid());fflush(stdout);
}
else if (dir == 2){
printf("der ");
printf("child pid %d parent pid %dn",getpid(),getppid());fflush(stdout);
}
}
void vector(int vector[], int length, int niveles){
for(int i=1;i<=niveles;i++)
{
int error = 0;
pid_t child_pid[2] = { -1, -1 };
for (int dir=0; dir<=1; ++dir) {
child_pid[dir] = fork();
if (child_pid[dir] == -1) {
error = 1;
perror("fork");
}
if (child_pid[dir] == 0) {
// Here is where you place the code the child should execute.
slice(dir);
exit(0);
}
}
for (int dir=0; dir<=1; ++dir) {
if (child_pid[dir] == -1)
continue;
int status;
pid_t pid = waitpid(child_pid[dir], &status, 0);
if (pid == -1) {
error = 1;
perror("waitpid");
}
else if (WIFSIGNALED(status)) {
error = 1;
fprintf(stderr, "Child was killed by signal %dn", WTERMSIG(status));
}
else if (WEXITSTATUS(status) != 0) {
error = 1;
fprintf(stderr, "Child exited with error %dn", WEXITSTATUS(status));
}
}
if (error)
exit(1);
}
}
我的目标是为"izq"调用一个函数,该函数在保持整个二叉树思想的同时,执行与"der"不同的事情。
请记住,父级和子级都从fork
继续执行,因此您需要如下所示的内容:
int error = 0;
pit_t child_pid[2] = { -1, -1 };
for (int dir=0; dir<=1; ++dir) {
child_pid[dir] = fork();
if (child_pid[dir] == -1) {
error = 1;
perror("fork");
}
if (child_pid[dir] == 0) {
// Here is where you place the code the child should execute.
exit(0);
}
}
for (int dir=0; dir<=1; ++dir) {
if (child_pid[dir] == -1)
continue;
int status;
pid_t pid = waitpid(child_pid[dir], &status, 0);
if (pid == -1) {
error = 1;
perror("waitpid");
}
else if (WIFSIGNALED(status)) {
error = 1;
fprintf(stderr, "Child was killed by signal %dn", WTERMSIG(wstatus));
}
else if (WEXITSTATUS(status) != 0) {
error = 1;
fprintf(stderr, "Child exited with error %dn", WEXITSTATUS(wstatus));
}
}
if (error)
exit(1);