我需要完成mysql_query选择多个选项并在网页上发布结果。表单(Breezingforms(拉取数据。
Joomla模块将出现在网页上
<div id="frmSrchResults"></div>
表单上的"搜索"按钮,用户可选择从数据库中提取数据
function ff_Searchbutton_action(element, action)
{
switch (action) {
case 'click':
let var1 = ff_getElementByName('category').value;
let var2 = ff_getElementByName('subcategory').value;
let var3 = ff_getElementByName('CselCountry').value;
// call the .post
jQuery.ajaxSetup({async:false});
jQuery.post(
'<?php return JUri::root(true); ?>/index.php', {
option: 'com_breezingforms',
ff_form: ff_processor.form,
format: 'html',
category: var1,
subcategory: var2,
country: var3
},
// success: function(data) {
function(data) {
jQuery('#frmSrchResults').html(data);
);
break;
default:;
} // switch
} // ff_Searchbutton_action
在表单片段中 - 在表单之前
$this->execPieceByName('ff_InitLib');
// fetch .post() parameters
$var1 = JRequest::getVar('par1');
$var2 = JRequest::getVar('par2');
if ($var1 && $var2 && $var1 !== '' && $var2 !== '') {
$db = JFactory::getDBO();
$db->setQuery("Query I need to complete");
$result = $db->loadAssocList();
// clean output buffer
while (@ob_get_level() > 0) { @ob_end_clean(); }
echo $result;
exit;
}
这是数据库结构的一个示例
id title name value
4 Company Name companyname Microsoft
4 Company Address companyaddress someaddress
4 Country country USA
4 Category category Computer
4 Sub-category subcategory Software
5 Company Name companyname Apple
5 Company Address companyaddress someaddress2
5 Country country CANADA
5 Category category Business
5 Sub-category subcategory Executive
6 Company Name companyname Ollivetti
6 Company Address companyaddress someaddress3
6 Country country CANADA
6 Category category Business
6 Sub-category subcategory Executive
例如,用户输入的表格:
Category=Business
Sub-category=Executive
Country=CANADA
现在我需要:选择值(根据用户在表单上的选择。每个表单元素都是一个选择列表(FROM 表等。 所以在我的例子中,结果应该是这样的:
Company Name Company Address
Apple someaddress2
Ollivetti someaddress3
我假设您正在运行过时的Joomla版本,因为JRequest在Joomla 3.x和Joomla 3.3中已被弃用,JRequest::getVar((因此,您应该尽快升级。
现代语法:
$jinput = JFactory::getApplication()->input;
$category = $jinput->get->post('par1', '', 'WORD');
$subcategory = $jinput->get->post('par2', '', 'WORD');
$country = $jinput->get->post('par3', '', 'WORD');
然后你可以像这样编写你的条件:
if ($category && $subcategory && $country) {
您的查询需要使用"透视"对关联的行进行分组;这是我在Joomla Stack Exchange上发布的一个解决方案,它实现了透视。
SQL搜索Business
和Executive
:(db-fiddle演示(
SELECT
MAX(CASE WHEN `name` = 'companyname' THEN `value` ELSE NULL END) AS `Company Name`,
MAX(CASE WHEN `name` = 'companyaddress' THEN `value` ELSE NULL END) AS `Company Address`
FROM `ucm`
GROUP BY `id`
HAVING
MAX(CASE WHEN `name` = 'category' THEN `value` ELSE NULL END) = 'Business'
AND MAX(CASE WHEN `name` = 'subcategory' THEN `value` ELSE NULL END) = 'Executive'
AND MAX(CASE WHEN `name` = 'country' THEN `value` ELSE NULL END) = 'CANADA'
ORDER BY `Company Name`;
使用输入变量将此原始SQL转换为Joomla方法语法,它看起来像这样:
$db = JFactory::getDbo();
$query = $db->getQuery(true)
->select([
"MAX("
. "CASE WHEN name = " . $db->q("companyname")
. " THEN value ELSE NULL END"
. ") AS " . $db->qn("Company Name"),
"MAX("
. "CASE WHEN name = " . $db->q("companyaddress")
. " THEN value ELSE NULL END"
. ") AS " . $db->qn("Company Address")
])
->from($db->qn("#__your_ucm_table"))
->group("id")
->having([
"MAX("
. "CASE WHEN name = " . $db->q("category")
. " THEN value ELSE NULL END"
. ") = " . $db->q($category),
"MAX("
. "CASE WHEN name = " . $db->q("subcategory")
. " THEN value ELSE NULL END"
. ") = " . $db->q($subcategory),
"MAX("
. "CASE WHEN name = " . $db->q("country")
. " THEN value ELSE NULL END"
. ") = " . $db->q($country)
])
->order($db->qn("Company Name"));
try
{
$db->setQuery($query);
if (!$results = $db->loadAssocList())
{
echo "No matches found";
}
else
{
echo "<table>";
echo "<tr><th>", implode("</th><th>", array_keys($results[0])), "</th></tr>";
foreach ($results as $row)
{
echo "<tr><td>", implode("</td><td>", $row), "</td></tr>";
}
echo "</table>";
}
}
catch (Exception $e)
{
JFactory::getApplication()->enqueueMessage("<div>Query Syntax Error, ask dev to run diagnostics</div>", 'error');
// Don't show the following details to the public:
//echo $query->dump();
//echo $e->getMessage();
}
p.s. 请记住,您不能简单地echo
您的loadAssocList
数据。
至于你的jquery,我相信你错过了调用的success
块。
success: function (data) {
jQuery('#frmSrchResults').html(data);
},
error: function (xhr, status) {
console.log("Bonk! Time to debug.");
}
以下是一些上下文: https://stackoverflow.com/a/20008285/2943403