我有一个TextInputLayout
,PasswordToggle
我的一个密码EditText
如下所示,
<android.support.design.widget.TextInputLayout
android:id="@+id/password_input_layout"
android:layout_width="match_parent"
android:layout_height="@dimen/text_input_height"
android:gravity="center"
app:passwordToggleDrawable="@drawable/password_visibility"
app:passwordToggleEnabled="true">
<android.support.v7.widget.AppCompatEditText
android:id="@+id/register_password_edittext"
android:layout_width="match_parent"
android:layout_height="@dimen/appcompat_editText_height"
android:hint="@string/register_password"
android:imeOptions="actionNext"
android:inputType="textPassword"/>
</android.support.design.widget.TextInputLayout>
现在我也TextWatcher
为这个密码实现了EditText
来处理这样的验证,
passwordEditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
// Do validation here.
}
});
问题是,当用户单击TextInputLayout
的eye-icon
时,我的TextChangeListener
会无缘无故地触发,并且验证失败的块会不必要地执行。
如何避免这种情况?如何处理PasswordToggleIcon
点击操作?
passwordEditText.addTextChangedListener(new TextWatcher() {
String textBeforeChange;
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
textBeforeChange = s.toString();
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
if (!textBeforeChange.equals(s.toString)) {
// Do validation here.
}
}
});
如果文本没有改变,那么我想没有必要进行验证?可能我错过了你问题的意图。干杯!