循环时用户输入出口要断开

Question

我正在为计算机进行分配以生成一个随机数并使用户输入他们的猜测。问题是我应该为用户提供输入"退出"的选项，并且会破坏循环。我究竟做错了什么？我正在运行它，它说线猜= int有问题(输入("猜测1至9："的数字："(

(

import random
num = random.randint(1,10)
tries = 1
guess = 0
guess = int(input("Guess a number from 1 to 9: "))
while guess != num:
    if guess == num:
        tries = tries + 1
        break
    elif guess == str('Exit'):
        break
    elif guess > num:
        guess = int(input("Too high! Guess again: "))
        tries = tries + 1
        continue
    else:
        guess = int(input("Too low! Guess again: "))
        tries = tries + 1
        continue
print("Exactly right!")
print("You guessed " + str(tries) + " times.")

Answer 1

最简单的解决方案可能是创建一个函数，该函数将显示的消息作为输入获取并在测试其满足您的条件后返回用户输入：

def guess_input(input_message):
    flag = False
    #endless loop until we are satisfied with the input
    while True:
        #asking for user input
        guess = input(input_message)
        #testing, if input was x or exit no matter if upper or lower case
        if guess.lower() == "x" or guess.lower() == "exit":
            #return string "x" as a sign that the user wants to quit
            return "x"
        #try to convert the input into a number
        try:
            guess = int(guess)
            #it was a number, but not between 1 and 9
            if guess > 9 or guess < 1:
                #flag showing an illegal input
                flag = True
            else:
                #yes input as expected a number, break out of while loop
                break
        except:
            #input is not an integer number
            flag = True
        #not the input, we would like to see
        if flag:
            #give feedback
            print("Sorry, I didn't get that.")
            #and change the message displayed during the input routine
            input_message = "I can only accept numbers from 1 to 9 (or X for eXit): "
            continue
    #give back the guessed number
    return guess

您可以在主计划中从

中调用此功能

#the first guess
guess = guess_input("Guess a number from 1 to 9: ")

或

#giving feedback from previous input and asking for the next guess
guess = guess_input("Too high! Guess again (or X to eXit): ")

Answer 2

您正在尝试将字符串'出口'到整数。您可以添加一个尝试/除外，除了铸件周围并处理无效的输入。

import random
num = random.randint(1,9)
tries = 1
guess = 0
guess = input("Guess a number from 1 to 9: ")
try:
  guess = int(guess) // try to cast the guess to a int
  while guess != num:
    if guess == num:
        tries = tries + 1
        break
    elif guess > num:
        guess = int(input("Too high! Guess again: "))
        tries = tries + 1
        continue
    else:
        guess = int(input("Too low! Guess again: "))
        tries = tries + 1
        continue
  print("Exactly right!")
  print("You guessed " + str(tries) + " times.")    
except ValueError: 
    if guess == str('Exit'):
      print("Good bye")
    else:  
      print("Invalid input")