服务器结果带有错误

Question

我在PHP中执行POST请求，服务器在发布完成后发回一些文本。 这是代码：

<?php  // Create map with request parameters
$params = array ('username' => 'loginapi', 'password' => 'myapilogin', 'term'=>  'tema'     );
// Build Http query using params
$query = http_build_query ($params);
// Create Http context details
$contextData = array (
            'method' => 'POST',
            'header' => "Connection: closern".
                        "Content-Length: ".strlen($query)."rn",
            'content'=> $query );
// Create context resource for our request
$context = stream_context_create (array ( 'http' => $contextData ));
// Read page rendered as result of your POST request
$result =  file_get_contents (
              'http://infolinetest.nandiclient.com/search/searches/requestData.xml',  // page url
              false,
              $context);
// Server response is now stored in $result variable so you can process it
var_dump($result);
?>

问题是即使我想要的结果如下，也会发生以下错误：

Notice: file_get_contents() [function.file-get-contents]: Content-type not specified      
assuming application/x-www-form-urlencoded in C:xampphtdocsdirectory               Search_Result.php on line 49
string(269) " Nandimobile
19 Banana Street, American House East legon
IT Software products and services0302503313 0244709575 " 

提前感谢

Answer 1

您需要为 POST 指定内容类型。

$contextData = array (
            'method' => 'POST',
            'header' => "Connection: closern".
                        "Content-Type: application/x-www-form-urlencodedrn".
                        "Content-Length: ".strlen($query)."rn",
            'content'=> $query );

Answer 2

1，您没有收到您所说的错误，这只是通知（您可以在php.ini配置中禁用它）

2，您可以通过像这样设置内容类型标头来简单地避免此问题：

$contextData = array (
        'http'=>array(
            'method' => 'POST',
            'header' => "".
                "Connection: closern".
                "Content-Length: ".strlen($query)."rn".
                "Content-type: "."application/x-www-form-urlencoded"."rn",
            "content"=> $query )
         );

更多信息在这里 ： http://php.net/manual/en/function.stream-context-create.php

Answer 3

在file_get_contents之前添加@并尝试

$result =  @file_get_contents (
              'http://infolinetest.nandiclient.com/search/searches/requestData.xml',  // page url
              false,
              $context);