我试图在具有3个片段的活动上实现on式倾斜。我的问题是,我在一段时间方法后实现了"再次按要退出",但是当单击两次后按钮时,它返回到上一个片段而不是退出。当调用该片段时,就会发生这种情况(即,如果我打开游戏并立即退出,它像魅力一样起作用)。我对主活动的on式压制方法看起来像这样;
@Override
public void onBackPressed() {
if(getSupportFragmentManager().getBackStackEntryCount()!=0) {
getSupportFragmentManager().popBackStack();
}
this.findViewById(R.id.linearLayout1).setVisibility(View.VISIBLE);
if(mBackPressed + TIME_INTERVAL > System.currentTimeMillis() && getSupportFragmentManager().getBackStackEntryCount()==0){
super.onBackPressed();
System.exit(0);
this.finish();
}
else { Toast.makeText(getBaseContext(), "Press back once more to exit", Toast.LENGTH_SHORT).show(); }
mBackPressed = System.currentTimeMillis();
}
我基本上想检查用户是否处于MainActivity布局中,以便我可以使用PopBackStack逃避。任何解决方案都将不胜感激,如果这还不够,我可以提供更多信息。
谢谢bektaş
如果您真的想退出,请完全忽略背面堆栈。使用此代码。
@Override
public void onBackPressed() {
this.findViewById(R.id.linearLayout1).setVisibility(View.VISIBLE);
if(mBackPressed + TIME_INTERVAL > System.currentTimeMillis()){
this.finish();
return;
}
else {
Toast.makeText(getBaseContext(), "Press back once more to exit", Toast.LENGTH_SHORT).show();
}
mBackPressed = System.currentTimeMillis();
}
我认为您可能会发现此链接有用http://developer.android.com/training/implementing-navigation/temporal.html
它说您可以使用此paturn
将引用添加到堆栈中// Works with either the framework FragmentManager or the
// support package FragmentManager (getSupportFragmentManager).
getSupportFragmentManager().beginTransaction()
.add(detailFragment, "detail")
// Add this transaction to the back stack
.addToBackStack()
.commit();
@Override
public void onBackPressed() {
int count = getSupportFragmentManager().getBackStackEntryCount();
if (count == 0) {
getSupportFragmentManager().popBackStack(getSupportFragmentManager().getBackStackEntryCount(), getSupportFragmentManager().POP_BACK_STACK_INCLUSIVE);
android.app.AlertDialog.Builder builder = new android.app.AlertDialog.Builder(context);
builder.setCancelable(false);
builder.setMessage("Are you sure you want to exit?")
.setNegativeButton(android.R.string.no, null)
.setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
(Main Activity Name).super.onBackPressed();
}
}).create().show();
} else {
super.onBackPressed();
}
}