如何在lwjgl/slick2d中播放一次循环播放声音

Question

我想在Mainmenu中的鼠标内部按钮中放入鼠标时一次播放声音效果。问题在这里 - Mainmenu处于循环状态，所以我的声音一直都在重复。当某人将鼠标放在内部按钮中时，如何播放一次声音？

按钮：

if(mouse is in position X = <0,100> and Y = <0,100>){
    drawButton( X = 0, Y = 0, X2 = 100, Y2 = 100);
}

按钮在循环中：

while( we are in MainMenu state )
{
    if(mouse is in position X = <0,100> and Y = <0,100>){
        drawButton( X = 0, Y = 0, X2 = 100, Y2 = 100);
    }
}

声音：

Music Sound_1 = new Music("res/Sound/Sound_1.wav");

播放声音：

Sound_1.play(1.0f, 1.0f);

代码：

while( we are in MainMenu state )
{
    if(mouse is in position X = <0,100> and Y = <0,100>){
        Sound_1.play(1.0f, 1.0f); <- IT MUST PLAY JUST ONCE WHENEVER MOUSE IS IN BUTTON
        drawButton( X = 0, Y = 0, X2 = 100, Y2 = 100);
    }
}

Answer 1

您可以通过调用声音检查是否已经播放（使用示例声音变量_1）：

if(mouse is in position) {
    if(!sound_1.playing()) {
        sound_1.play(1.0f, 1.0f);
    }
    drawButton(x,y,x2,y2);
}

使用Sound/Music对象具有光滑的.playing（）方法，如果声音当前播放，它将返回boolean true，如果不是，则false。希望这会有所帮助：）

Answer 2

在调用循环之前，添加一个布尔值，该布尔值跟踪游戏是否应该播放声音：

boolean playSound = false;

然后，当您调用循环时，请执行此操作：

    loop() {
        playSound = true;
        if (/**Mouse is on the button*/) {playSound = true;}
        else {playSound = false}
        //If playSound is true, then play the sound
        if (playSound) {sound.play(1.0f, 1.0f);}
        else 
            return;
     }

应该起作用！

Answer 3

您需要设置一个布尔值来确定我们是否已经播放了声音。

boolean soundHasPlayed = false;
while( we are in MainMenu state )
{
    if(mouse is in position X = <0,100> and Y = <0,100>){
        if (!soundHasPlayed) // only do this if we haven't played the sound yet
        {
            Sound_1.play(1.0f, 1.0f);
            drawButton( X = 0, Y = 0, X2 = 100, Y2 = 100);
            soundHasPlayed = true; // don't play it again until we leave the button
        }
    }
    else
    {
        // We left the button, so we can play it again if we ever enter the button again.  
        // (Omit this if you really only want it to play once, ever, even if they mouse over the button again.)
        soundHasPlayed = false;
    }
}