为什么 try 块中引发的异常后的代码没有执行?如果未处理异常，则控件将消失

Question

class TestFinallyBlock1{  
    public static void main(String args[]){  
        try{  
            int data=25/0;  
            System.out.println(data);  
        }  
        catch(NullPointerException e){System.out.println(e);}  
        finally{System.out.println("finally block is always executed");}  
        System.out.println("rest of the code...");  
    }  
} 

Answer 1

我认为如果您提取方法并添加额外的 try-catch 块，您可以理解该行为，如下所示：

public class TestFinallyBlock1 {
    public static void main(String args[]) {
        try {
            throwArithmeticException();
            System.out.println("rest of the code...");
        } catch (ArithmeticException e) {
            System.out.println(e);
        }
    }
    private static void throwArithmeticException() {
        try {
            int data = 25 / 0;
            System.out.println(data);
        } catch (NullPointerException e) {
            System.out.println(e);
        } finally {
            System.out.println("finally block is always executed");
        }
    }
}

有关更多详细信息，请参阅 Java 语言规范 - 执行 try-finally 和 try-catch-finally