r语言 - 补体功能

Question

我的数据：

a <- c('KK','LL','II','JJ','AA','CC','GG','FF','EE','QQ','ZZ','XX')
b <- c('CC','GG','FF','EE','KK','LL','II','JJ','QQ','ZZ','XX','BB','AA','OO','WW')

目标：列出所有「B」有但「A」没有的东西

我尝试：

union(a,b)
[1] "KK" "LL" "II" "JJ" "AA" "CC" "GG" "FF" "EE" "QQ" "ZZ" "XX" "BB" "OO"
[15] "WW"
intersect(a,b)
[1] "KK" "LL" "II" "JJ" "AA" "CC" "GG" "FF" "EE" "QQ" "ZZ" "XX"

Answer 1

如果这是 R 语言：

setdiff(b, a)

另请参阅有关片场操作的文档