我该如何解决这个问题？ "Unsupported operand type(s)"

Question

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = numbers[0] + numbers[1] + numbers[2]
  final = int(judge_scores)
  final_2 = sum(final)
  print(final_2)

i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

我试图让这段代码返回评委为每个运动员给出的随机分数的总和，但我遇到一个错误，说

int 对象不可迭代。

我已经稍微改变了它，但没有运气，这是我认为最接近的原始代码：

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = numbers[0] + numbers[1] + numbers[2]
  final = sum(judge_scores)
  print(final)

i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

我再次遇到错误。 这次我收到此错误：

类型错误： + 不支持的操作数类型："int"和"str">

Answer 1

您可以将数字列表中的字符串值更改为 int，如下所示：

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = [1,2,3,4,5,6,7,8,9,10]
def score():
  random.shuffle(numbers)
  judge_scores = numbers[0] + numbers[1] + numbers[2]
  print(judge_scores)

i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

或者您可以使用

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = int(numbers[0]) + int(numbers[1]) + int(numbers[2])
  print(judge_scores)

i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

Answer 2

您是否有一个带有数字的列表，因为str尝试将数字更改为数字 = [1,2,3,4,5,6,7,8,9,10]

Answer 3

判断字符串分数，sum适用于 int 类型，您需要先将搅拌转换为 int，然后进行求和运算

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = [numbers[0] , numbers[1] , numbers[2]]
  final = sum(map(int,judge_scores))
  print(final)

i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

Answer 4

sum 采用可迭代对象并对其值求和。在您的情况下，numbers包含字符串，因此它会连接字符串：('2', '5', '7')转到'257'。在[1,2,...]中更改您的numbers列表，一切都会好起来的。

另外，您只需输入即可

numbers = list(range(10))