我一直在构建模板链表,最近实现了用户定义的复制构造函数来处理我的链表的深层副本。 我当前的解决方案编译得很好,但是当我执行时,什么都没有显示。
#include <iostream>
template<typename T>
class LinkedList
{
private:
struct Node
{
T data;
Node* next;
};
Node* head;
Node* tail;
int size;
public:
LinkedList();
LinkedList(const LinkedList<T> &list);
~LinkedList();
LinkedList<T>& operator=(const LinkedList<T> list);
int getSize() const;
void display() const;
void push(const T &data);
void insert(const int pos, const T &data);
void remove(const int pos);
};
template<typename T>
LinkedList<T>::LinkedList() : head{ nullptr }, tail{ nullptr }, size{ 0 }
{
}
// TODO: User-defined copy constructor
template<typename T>
LinkedList<T>::LinkedList(const LinkedList<T> &list)
: head{ nullptr }, tail{ nullptr }, size{list.size}
{
std::cout << "In the copy constructorn";
if (list.head == nullptr)
{
return;
}
else
{
Node* curNode = new Node{list.head->data, nullptr};
head = curNode; // sets the head member variable to first node in Linked List
Node* curListNode = list.head;
while (curListNode->next != nullptr)
{
curNode->next = new Node{curListNode->next->data, nullptr};
curListNode = curListNode->next;
curNode = curNode->next;
}
curNode->next = new Node{curListNode->next->data, nullptr};
tail = curNode->next;
}
}
template<typename T>
LinkedList<T>::~LinkedList()
{
Node* prevNode = head;
Node* curNode = head;
while(curNode != nullptr)
{
prevNode = curNode;
curNode = curNode->next;
delete prevNode;
}
head = nullptr;
tail = nullptr;
}
template<typename T>
LinkedList<T>& LinkedList<T>::operator=(const LinkedList<T> list)
{
// make a copy of each node - much like the copy constructor
std::cout << "In the overloaded assignmentn";
}
template<typename T>
int LinkedList<T>::getSize() const
{
return size;
}
template<typename T>
void LinkedList<T>::display() const
{
Node* curNode = head;
while (curNode != nullptr)
{
std::cout << curNode->data << 'n';
curNode = curNode->next;
}
std::cout << 'n';
}
template<typename T>
void LinkedList<T>::push(const T &data)
{
Node* newNode = new Node{data, nullptr};
if (size == 0)
{
head = newNode;
tail = newNode;
}
else
{
tail->next = newNode;
tail = newNode;
}
++size;
}
template<typename T>
void LinkedList<T>::insert(const int pos, const T &data)
{
if (pos < 0 || pos > size)
{
throw "Index is out of range!";
}
else if (pos == size)
{
push(data);
}
else
{
Node* newNode = new Node{data, nullptr};
Node* prevNode = head;
Node* curNode = head;
int i = 0;
while (i != pos)
{
prevNode = curNode;
curNode = curNode->next;
++i;
}
prevNode->next = newNode;
newNode->next = curNode;
++size;
}
}
template<typename T>
void LinkedList<T>::remove(const int pos)
{
if (pos < 0 || pos > size)
{
throw "Index is out of range!";
}
else if (size == 0)
{
throw "List is empty!";
}
else
{
Node* prevNode = head;
Node* curNode = head;
int i = 1;
while (i != pos)
{
prevNode = curNode;
curNode = curNode->next;
++i;
}
prevNode->next = curNode->next;
delete curNode;
if (pos == size)
{
tail = prevNode;
}
--size;
}
}
int main()
{
LinkedList<int> list;
list.push(1);
list.push(3);
list.push(6);
list.display();
LinkedList<int> copyList{list};
copyList.display();
return 0;
}
当我将 copyList
语句添加到 main()
时,第一个LinkedList<int> list
甚至没有显示。 但是,当我注释掉两个copyList
语句时,list
正常显示。
我添加了 print 语句以查看是否调用了复制构造函数或 operator=
函数,并且当copyList
语句添加到我的程序中时,它们都不会打印到控制台(代码编译得很好(。
我可以使用任何帮助来帮助诊断导致此行为的原因。
像这样的简单复制构造函数就足够了:
template<typename T>
LinkedList<T>::LinkedList(const LinkedList<T> &list)
: head{ nullptr }, tail{ nullptr }, size{0}
{
std::cout << "In the copy constructorn";
Node* curNode = list.head;
while (curNode != nullptr)
{
this->push(curNode->data);
curNode = curNode->next;
}
}
请注意,这只是重写display
方法以在当前列表中插入元素。