我正在尝试在我的 ajax 调用中记录来自我的 servlet 的 json 响应。现在，事情是这样的，我尝试在我的 ajax 中尝试记录字符串响应，事情似乎工作正常，但后来我尝试记录 json 响应，我在控制台中什么也没看到。我想知道我是否错过了什么。我尝试从POSTMAN调用我的servlet，我得到了正确的json响应。
家服务员.java
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
Map<String, String> options = new LinkedHashMap<>();
String text = "some text";
PrintWriter out = response.getWriter();
response.setContentType("text/html");
try {
Class.forName("com.mysql.jdbc.Driver");
Connection con= (Connection) DriverManager.getConnection("jdbc:mysql://localhost/apiprovider","root","");
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery("select * from apiinfo");
// out.println("<table border=1 width=50% height=50%>");
// out.println("<tr><th>EmpId</th><th>EmpName</th><th>Salary</th><tr>");
while (rs.next()) {
String n = rs.getString("apiname");
String nm = rs.getString("apiendpoint");
options.put("value1", n);
options.put("value2", nm);
String json = new Gson().toJson(options);
response.setContentType("application/json");
response.setCharacterEncoding("UTF-8");
response.getWriter().write(json);
// out.println("<tr><td>" + n + "</td><td>" + nm + "</td><td>" + s + "</td></tr>");
}
// out.println("</table>");
// out.println("</html></body>");
con.close();
}
catch (Exception e) {
out.println("error");
}
}
首页.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<div id="ajaxresponse">
</div>
<form>
API Name:<br>
<input type="text" id = "apiname" name="apiname">
API ENDPOINT:<br>
<input type="text" id ="apiendpoint" name="apiendpoint">
<br>
API VERSION:<br>
<input type="text" id="apiversion" name="apiversion">
ACCESSIBLE:<br>
<input type="checkbox" name="source" value="internet"> Internet<br>
<input type="checkbox" name="source" value="vpn"> VPN<br>
<!--
<br><br>
<input type="submit" formaction="Home" method="post" value="Submit"> -->
<br>
<input type="submit" id="check" name="check" value="Check">
</form>
<script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
<script type="text/javascript">
$(document).on("click", "#check", function() { // When HTML DOM "click" event is invoked on element with ID "somebutton", execute the following function...
console.log("I was clicked");
$.get("HomeServlet", function(responseText) {
console.log("response",responseText);
// Locate HTML DOM element with ID "somediv" and set its text content with the response text.
});
});
</script>
</body>
</html>
你需要写一个回调，这将在你的ajax调用完成时触发，尝试如下
function success(data) {
console.log( data );
}
function failure(err) {
console.error( err );
}
ajax( "http://some.url.1", success, failure );