我正在派遣一个看起来像这样的动作:
{ type: "TOGGLE_FARA", fara: true, id: "5d20d019cf42731c8f706db1" }
" ID"仅用于识别正确的用户。该动作旨在修改我的"法拉"状态的"启用"属性。我商店的法拉部分看起来像这样:
{
fara: {
enabled: false, // This need to be flipped...
names: []
},
senators: {
enabled: false,
names: []
},
senateCandidates: {
enabled: false,
names: []
}
}
但是,我不确定如何构建还原器。我只想更改"启用"属性。我尝试了几种不同的方法:
export default (state = DEFAULT_STATE, action) => {
switch (action.type) {
case "INITIALIZE_SETTINGS":
return {
fara: action.fara,
senators: action.senators,
senateCandidates: action.senateCandidates,
emails: action.emails
}
case "TOGGLE_FARA":
return {
...state,
// fara['enabled']: action.fara <–– This won't compile...
// 'fara.enabled' : action.fara <–––This just gives me a key name with the string 'fara.enabled'
}
default:
return state;
}
我要做这样的事情,但是这直接修改了您不应该这样做的状态(我的Redux工具扩展名称状态是相同的,这不是理想的(。有任何想法吗?
export default (state = DEFAULT_STATE, action) => {
switch (action.type) {
case "INITIALIZE_SETTINGS":
return {
fara: action.fara,
senators: action.senators,
senateCandidates: action.senateCandidates,
emails: action.emails
}
case "TOGGLE_FARA":
state.fara.enabled = action.fara;
return {
...state
};
default:
return state;
}
这将有效:
return {
...state,
fara: { ...state.fara, enabled: action.fara }
}
显然甚至在Redux文档中