在设置值之前检查请求输入是否不为 null

Question

我有一个设置用户设置的API。由于这两个输入都不是必需的，我想首先检查该值是否存在，然后将其设置为模型属性以避免空值。

$this->InputValidator->validate($request, [
                'firsname' => 'string',
                'lastname' => 'string',
                'email' => 'email',
                'mobile_phone' => 'string',
                'address' => 'string',
                'language' => 'string',
                'timezone' => 'string',
                'nationality' => 'string',
                'profile_photo' => 'url'
            ]);
            $userInformation = new UserInformation([
                'firstname' => $request->input('firstname'),
                'lastname' => $request->input('lastname'),
                'email' => $request->input('email'),
                'mobile_phone' => $request->input('mobile_phone'),
                'address' => $request->input('address'),
                'profile_photo' => $request->input('profile_photo')
            ]);
            $User->information()->save($userInformation);

具体来说，当其中一个输入不存在时，我不想将其传递给模型。我也不想输入

Answer 1

这个

问题的答案来自这里：

if($request->filled('user_id'))

Answer 2

这样做

$userInformation = new UserInformation;
if(request->has('firstname')){
   $userInformation->firstname = $request->firstname;
}
if(request->has('lastnme')){
   $userInformation->lastname = $request->lastname;
}
 // do it for all
 $User->information()->save($userInformation);

编辑：或使用表单请求，这是一种更好的方法

Answer 3

检查每个值并首先将其推送到数组中。然后分配数组。

<?php
$userArray=array();
if($request->input('firstname') != "") $userArray['firstname']=$request->input('firstname');
if($request->input('lastname') != "") $userArray['lastname']=$request->input('lastname');
if($request->input('email') != "") $userArray['email']=$request->input('email');
if($request->input('mobile_phone') != "") $userArray['mobile_phone']=$request->input('mobile_phone');
if($request->input('address') != "") $userArray['address']=$request->input('address');
if($request->input('profile_photo') != "") $userArray['profile_photo']=$request->input('profile_photo');
$userInformation = new UserInformation($userArray);
?>

Answer 4

$request->validate([
  'name'=>['required'],
])

和

if(!is_null($request->name)){}