在模态PHP HTML中获取一个值

Question

这是我的代码，我应该在模态之外获得"$pw"。。但我似乎无法获取它的值，而且我似乎也无法获取"$errMSG"值。。如果是If($pin！=$pww(无法获得错误MESSAGE。。真的需要一些帮助。。非常感谢。

这是我的"$pw"代码，它与我的modal在同一页上。。

<?php 
include('connectdb.php');
$sql = "SELECT * FROM accounts WHERE usernamee='$userid'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($data = $result->fetch_assoc()) {
$pww = $data['passwordd'];
}
}
?>

这是我的模式代码：

<div class="container">
<form method="post">
<h2>Enter your Pin Number</h2>
<!-- Trigger the modal with a button -->
<button type="button" class="btn btn-info btn-lg" data-toggle="modal" data-target="#myModal">Open Modal</button>
<!-- Modal -->
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">&times;</button>
<h4 class="modal-title">Enter your Pin Number</h4>
</div>
<div class="modal-body text-center">
<input type="password" id="first-name" required="required" class="form-control" name="pin">
<?php
if(isset($errMSG)){
?>
<div class="alert alert-danger">
<span class="glyphicon glyphicon-infos-sign"></span> <strong><?php echo $errMSG; ?></strong>
</div>
<?php
}
else if(isset($successMSG)){
?>
<div class="alert alert-success">
<strong><span class="glyphicon glyphicon-info-sign"></span> <?php echo $successMSG; ?></strong>
</div>
<?php
}
?>
</div>
<div class="modal-footer">
<button type="submit" name="submit3" class="btn btn-default"><i class="fa fa-key"></i> Confirm Pin</button>
</div>
</div>             
</div>
</div>
<!-- START OF PHP -->
<?php include ('connectdb.php');
if(isset($_POST['submit3']))
{    
$pin = $_POST["pin"];
if ($pin != $pww) {
$errMSG= "WRONG PIN.. TRY AGAIN..";
}
else{
header('Location: myorders.php');
}
} // SUBMIT 
?>
</form>
</div>

Answer 1

include('connectdb.php');
$pww = '';
$sql = "SELECT * FROM accounts WHERE usernamee='$userid'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($data = $result->fetch_assoc()) {
$pww = $data['passwordd'];
}
}

请尝试以下代码，您应该在if或while括号之前声明pww，以获取对此变量的访问权限。