我需要读取其中一个模拟器的输出并存储这些值。文件名为forces.dat
,包含如下内容:
# Forces
# CofR : (4.750000e-01 3.500000e-02 2.000000e-02)
# Time forces(pressure viscous porous) moment(pressure viscous porous)
2.633022e-02 ((6.268858e-02 -1.468850e+01 1.542745e-20) (1.000906e-03 8.405854e-06 -5.657665e-17) (0.000000e+00 0.000000e+00 0.000000e+00)) ((-8.779466e-18 8.442993e-19 -3.225599e-03) (-2.082489e-18 4.435609e-18 -1.572485e-03) (0.000000e+00 0.000000e+00 0.000000e+00))
8.095238e-02 ((1.781333e-01 -1.468455e+01 -3.545427e-19) (2.362118e-03 2.014609e-05 1.691584e-16) (0.000000e+00 0.000000e+00 0.000000e+00)) ((-3.344781e-18 -5.448339e-19 2.227502e-02) (5.092628e-18 -3.538718e-18 -1.203074e-03) (0.000000e+00 0.000000e+00 0.000000e+00))
1.600000e-01 ((3.204471e-01 -1.467482e+01 -4.599174e-18) (6.936764e-03 1.303800e-04 4.836650e-17) (0.000000e+00 0.000000e+00 0.000000e+00)) ((-1.123589e-17 -4.344967e-19 5.591623e-02) (1.532415e-18 -1.345592e-18 -9.550750e-04) (0.000000e+00 0.000000e+00 0.000000e+00))
我想知道我应该如何写一个Fortran子程序来忽略前3行,然后读取接下来的行数,然后是每行的值。
您可以使用这个代码片段,它将跟踪行号。根据您的要求和文件的性质,您可以获得各自行的值,并可以执行所需的操作。
string CurrentLine;
int LastLineNumber;
void NextLine()
{
// using will make sure the file is closed
using(System.IO.StreamReader file = new System.IO.StreamReader ("c:\forces.dat"))
{
// Skip lines
for (int i=0;i<LastLineNumber;++i)
file.ReadLine();
// Store your line
CurrentLine = file.ReadLine();
LastLineNumber++;
}
}
在上面的代码中,在for
循环中,您可以根据要读取的行放入文件处理的逻辑。
虽然我认为通过一些命令行工具(例如sed -e 's/(/ /g' -e 's/)/ /g' input.dat
)更容易预处理文件,但我们也可以直接使用Fortran,将每行读入长字符串并删除所有不必要的括号:
program main
implicit none
integer, parameter :: mxline = 5000 !! choose appropriately
integer i, ios, finp, nl
character(500) str
real, save :: time( mxline )
real, dimension( 3, mxline ), save :: &
frc_pres, frc_visc, frc_poro, &
mom_pres, mom_visc, mom_poro
finp = 10
open( finp, file="input.dat", status="old" )
nl = 0
do
read( finp, "(a)", iostat=ios ) str
if ( ios /= 0 ) exit
str = trim( adjustL( str ) )
!! Skip comment or blank lines.
if ( str(1:1) == "#" .or. str == "" ) cycle
!! Replace parentheses with space.
do i = 1, len_trim( str )
if ( str(i:i) == "(" .or. str(i:i) == ")" ) str(i:i) = " "
enddo
!! Read data from the string.
nl = nl + 1
read( str, * ) time( nl ), &
frc_pres( :, nl ), frc_visc( :, nl ), frc_poro( :, nl ), &
mom_pres( :, nl ), mom_visc( :, nl ), mom_poro( :, nl )
enddo
close( finp )
!! Check.
do i = 1, nl
print *
print *, "time = ", time( i )
print *, "frc_pres = ", frc_pres( :, i )
print *, "frc_visc = ", frc_visc( :, i )
print *, "frc_poro = ", frc_poro( :, i )
print *, "mom_pres = ", mom_pres( :, i )
print *, "mom_visc = ", mom_visc( :, i )
print *, "mom_poro = ", mom_poro( :, i )
enddo
end program
如果数据值可能变得非常大(例如,1.0e100),请考虑使用双精度实数,以免失去必要的精度。