C语言 创建 BlockType 结构的单向链表

Question

我正在尝试用这 3 个typedef struct（人、统计数据和车辆）创建一个单链表。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct{
  char name[22];
  char city[10];
  int yearBorn;
}  person;

typedef struct{
  int height[8];
  double weight[18];
  }  Stats;
typedef struct{
 char car[16];
 int horsepower[20];
}  vehicle;

typedef struct node {
   person   *p; 
   Stats *stat;
   vehicle *hp;
   struct node *next;
}NODE;
typedef struct {
   NODE *head, *tail;
}SLL;

int main(){
void insert(SLL *list, person p, vehicle hp,  Stats stat){

a = (NODE *)malloc(sizeof(p));
b = (NODE *)malloc(sizeof(hp));
c = (NODE *)malloc(sizeof(stat));
if(list->head == NULL){
 return NULL;
}
list -> head -> next = a;
list -> head -> next-> next  = b;
list -> head -> next-> next -> next = c;
list -> tail = c;

}


return 0;
}

我不断收到a，b和c的错误，说错误："a"未声明（首次在此函数中使用）。我只是想知道我是否正确执行此操作，以及此错误意味着什么。我非常感谢对我的代码的任何见解。谢谢。

Answer 1

问题就在这里

int main(){
    void insert(SLL *list, person p, vehicle hp,  Stats stat){

    a = (NODE *)malloc(sizeof(p));
    b = (NODE *)malloc(sizeof(hp));
    c = (NODE *)malloc(sizeof(stat));
      if(list->head == NULL){
         return NULL;
      }
    list -> head -> next = a;
    list -> head -> next-> next  = b;
    list -> head -> next-> next -> next = c;
    list -> tail = c;
    }
return 0;
}

如何在其他函数中定义函数?!!