XML验证XSD时出错

Question

我在Java中写下了以下代码，但始终返回true。即使我修改XML并使XSD不兼容，它仍然返回true。请看看。

public static boolean isValidXML(String filePath,String xsdFile){
    boolean bValue = true;
    SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
    try {
        DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
        documentBuilderFactory.setNamespaceAware(true);
        DocumentBuilder parser = documentBuilderFactory.newDocumentBuilder();
        Document document = parser.parse(new File(filePath));
        Schema schema = schemaFactory.newSchema(new File(xsdFile));
        Validator validator = schema.newValidator();
        final List<SAXParseException> exceptions = new LinkedList<SAXParseException>();
        validator.setErrorHandler(new ErrorHandler()
        {
          public void warning(SAXParseException exception) throws SAXException
          {
            exceptions.add(exception);
          }
          public void fatalError(SAXParseException exception) throws SAXException
          {
            exceptions.add(exception);
          }
          public void error(SAXParseException exception) throws SAXException
          {
            exceptions.add(exception);
          }
        });
        validator.validate(new DOMSource(document));
    } catch (SAXException e) {
        bValue = false;
        logger.error("Error while Validating the XML."+e);
        e.printStackTrace();
    } catch (ParserConfigurationException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return bValue;
}

Answer 1

在您的ErrorHandler接口实现中，尝试以下内容：

而不是

exceptions.add(exception);

做以下

throw exception;

您的实施可能会消耗验证异常。您也可以检查exceptions并根据其内容返回。您为什么要填写以后再也不会使用的列表？