我有一个标准的UINAvigation控制器,并按照正常的推动和弹出来推动我的屏幕。但是,我有一个屏幕,可以在按钮上的两个视图控制器之间切换,因此屏幕在顶部翻转另一个ViewController,反之亦然。您可以随意在它们之间切换。
现在,我希望返回按钮正常工作,因此我将顶视图控制器交换以实现以下操作:
-(IBAction)switchToSlowProductEntry:(id)sender
{
NSLog(@"Switching to slow product entry");
// Replace the top view with the findProductView
FindProductView *findProdView = [ProductViewInstances shared].findProductView;
NSMutableArray *views = [self.navigationController.viewControllers mutableCopy];
[views removeLastObject];
[views addObject:findProdView];
// if sender is nil then assume we started from the viewDidLoad so no animation
if(sender)
{
[UIView transitionWithView:self.navigationController.view duration:0.3 options:UIViewAnimationOptionTransitionFlipFromRight animations:^
{
[self.navigationController setViewControllers:views animated:NO];
}
completion:^(BOOL finished) {}];
}
else
[self.navigationController setViewControllers:views animated:NO];
NSLog(@"Views: %@", views);
[views release];
[ProductViewInstances shared].lastScreen = SlowProductEntryView;
}
-(IBAction)switchToQuickProductEntry:(id)sender
{
NSLog(@"Switching to fast product entry");
// Replace the top view with the findProductView
QuickOrderEntryView *quickProductView = [ProductViewInstances shared].quickProductView;
NSMutableArray *views = [self.navigationController.viewControllers mutableCopy];
[views removeLastObject];
[views addObject:quickProductView];
if(sender)
{
[UIView transitionWithView:self.navigationController.view duration:0.3 options:UIViewAnimationOptionTransitionFlipFromLeft animations:^
{
[self.navigationController setViewControllers:views animated:NO];
}
completion:^(BOOL finished) {}];
}
else
[self.navigationController setViewControllers:views animated:NO];
NSLog(@"Views: %@", views);
[views release];
[ProductViewInstances shared].lastScreen = QuickProductEntryView;
}
我对另一个屏幕有类似的代码。我正在使用ProductViewInstances类来维护两个视图控制器,因为我不希望这些类在屏幕上保持阶段时卸载。
当您想从这些屏幕上向前移动时,我会按正常推动到新屏幕。它起作用了,我回顾了我添加的产品后就回去了。如果我向后退,我回到上面的屏幕上,一切似乎正常。但是,当我按下自定义的后背按钮(如果向后按下,我需要进行处理),我会遇到问题。
PopviewController什么都不做。这是管理自定义返回按钮的基类中的代码。
-(void) viewDidLoad
{
self.navigationItem.leftBarButtonItem = [[[UIBarButtonItem alloc] initWithTitle:NSLocalizedString(@"Back", nil)
style:UIBarButtonItemStyleBordered
target:self
action:@selector(myCustomBack)] autorelease];
if(![ProductViewInstances shared].findProductView)
{
[ProductViewInstances shared].findProductView = [[FindProductView alloc] init];
[ProductViewInstances shared].findProductView.customer = self.customer;
}
if(![ProductViewInstances shared].quickProductView)
{
[ProductViewInstances shared].quickProductView = [[QuickOrderEntryView alloc] init];
[ProductViewInstances shared].quickProductView.customer = self.customer;
}
}
-(void) goBack
{
if([[ProductViewInstances shared].quickProductView checkIfItemsPending])
{
// Pop up dialog
UIAlertView * alert = [[UIAlertView alloc] initWithTitle:NSLocalizedString(@"Save Entries", nil)
message:NSLocalizedString(@"Your entries will be lost", nil)
delegate:self
cancelButtonTitle:NSLocalizedString(@"Cancel", nil)
otherButtonTitles:NSLocalizedString(@"Save", nil), nil];
[alert show];
[alert release];
}
else
{
// Remove rows from quick item entry screen
[[ProductViewInstances shared].quickProductView removeRowsFromtable];
if(didPressHome)
[self popToSpringBoard:YES];
else
[self.navigationController popViewControllerAnimated:YES];
}
}
因此,当我向后压时,我必须检查条目是否会丢失。流行板到跳板弹出几个屏幕,基本上调用以下内容:
NSArray *controllers = appDelegate.navigationController.viewControllers;
UIViewController *springboard = [controllers objectAtIndex:2];
[appDelegate.navigationController popToViewController:springboard animated:animated];
但是,popviewController动画呼叫什么都没做...就像从未发生过一样。
Donie
@selector(myCustomBack) will not call goBack unless you left out some code.