比较字符串- Lua

Question

我有一个文件(termino.txt)，全部用以下格式填充:

1. 付款
2. 2015 - 08 - 30 t13:22:53.108z
3. 去看医生
4. 2015 - 09 - 30 t13:22:53.108z
5. …

所有的偶数行都是RFC 3339形式的时间戳。我需要的是对比一下今天的日期和文件中的这些日期是否相同。我正在尝试这个:

  local function verifica(evt)
    local nome= ''
    local dia = ''
    local turn = 1
    local data = os.date("%x")
    local file = io.open("termino.txt", "r")
    while true do
         nome = dia
         line = file:read()
         dia = line
         if (turn %2 == 0) then
          > Here I need to compare "data" with "dia" that will receive string with RFC 3339 timestamp format.

         end
    turn ++ 
    end
end

我需要帮助来做这个比较!由于

Answer 1

local dia = '2015-10-6T13:22:53.108Z'
-- parse date info from the RFC 3339 timestamp
local year, month, day = dia:match('(%d+)-(%d+)-(%d+)')
-- get today's date from Lua, in table format
local today = os.date('*t')
-- compare
if    tonumber(year)  == today.year
  and tonumber(month) == today.month
  and tonumber(day)   == today.day then
    -- the dates match
end