Gridview图像与图标和文本

Question

@@ branislav -我照你说的做了。这对我来说是有效的但是当没有图片超过9n个文本时它也开始在第9个图片和文本的位置显示相同的第1个或随机的图片和文本

public class ImageAdapter extends BaseAdapter {
private Context mContext;
public ImageAdapter(Context c) {
    mContext = c;
}
public int getCount() {
    return mThumbIds.length;
}
public Object getItem(int position) {
    return null;
}
public long getItemId(int position) {
    return 0;
}
// create a new ImageView for each item referenced by the Adapter
public View getView(int position, View convertView, ViewGroup parent) {
    View v;
    if (convertView == null) {  // if it's not recycled, initialize some attributes
        LayoutInflater li = getLayoutInflater();
        v = li.inflate(R.layout.mainmenu, null);
        TextView tv = (TextView)v.findViewById(R.id.icon_text);
        tv.setText(mTextsIds[position]);
        ImageView iv = (ImageView)v.findViewById(R.id.icon_image);
        iv.setImageResource(mThumbIds[position]);
    } else {
        v = (View) convertView;
    }
    return v;
}

  private Integer[] mThumbIds = {
        R.drawable.hotel1, R.drawable.rest,R.drawable.dubaicityinfoicon_new,R.drawable.history1,R.drawable.geography,R.drawable.infoicon,R.drawable.infoicon,R.drawable.infoicon,R.drawable.parkmain,
};
// references to our texts
private String[] mTextsIds = {
        "Hotels","Restaurants","City Info","Dubai History","Geography Of Dubai","Useful Information","Embassies in Duabai","Museum's","park"
};

在这个过程中，它是完美的，直到博物馆，但公园它不工作;它在数组mThumbIds中显示任何随机图像和相关文本。是的，图像是可绘制的

Answer 1

您可以为它创建自定义适配器类

public class MyAdapter extends ArrayAdapter<BindData> {
    private LayoutInflater inflater;
    private int layoutId;
    public MyAdapter(Context context, int layoutId, BindData[] objects) {
        super(context, 0, objects);
        this.inflater = (LayoutInflater) context
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        this.layoutId = layoutId;
    }
    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        ViewHolder holder;
        if (convertView == null) {
            convertView = inflater.inflate(layoutId, parent, false);
            holder = new ViewHolder();
            holder.textView = (TextView) convertView.findViewById(R.id.textview);
            holder.imageView = (ImageView) convertView.findViewById(R.id.imageview);
            convertView.setTag(holder);
        } else {
            holder = (ViewHolder) convertView.getTag();
        }
        //BindData data = getItem(position);
        holder.textView.setText(titles[position]);
        holder.imageView.setImageBitmap(imgs[position]);
        return convertView;
    }
}

，这样调用

issueGridView = (GridView) findViewById(R.id.gvissue);  
        adapter =new MyAdapter(Issue.this, R.layout.issue_item, mDatas);
        issueGridView.setAdapter(adapter);

其中mdata为

public class BindData {
    Bitmap b;
    String title;
    BindData(Bitmap bitmap, String s) {
        this.b = bitmap;
        this.title = s;
    }
}
private BindData[] mDatas;
    static class ViewHolder {
        TextView textView;
        ImageView imageView;
    }

Answer 2

使用Map或HashMap对值进行配对，

HashMap<Integer, String> store = new HashMap<Integer, String>();
store.put(R.drawable.hotel1, "Hotels");