不带文件扩展名的Scandir阵列显示

Question

我使用以下内容在"html/"和链接路径中创建文件列表。

当我查看阵列时，它会显示，例如my_file_name.php

如何使数组只显示文件名而不显示扩展名？

$path = array("./html/","./link/");
$path2=  array("http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["PHP_SELF"])."/html/","http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["PHP_SELF"])."/link/");
$start="";
$Fnm = "./html.php";
$inF = fopen($Fnm,"w");
fwrite($inF,$start."n");
$folder = opendir($path[0]);
while( $file = readdir($folder) ) {
       if (($file != '.')&&($file != '..')&&($file != 'index.htm')) {
            $folder2 = opendir($path[1]);
            $imagename ='';
            while( $file2 = readdir($folder2) ) {
                if (substr($file2,0,strpos($file2,'.')) == substr($file,0,strpos($file,'.'))){
                    $imagename = $file2;
                }
            }
            closedir($folder2);
        $result="<li class="ui-state-default ui-corner-top ui-tabs-selected ui-state-active">n<a href="$file">n$file2n</a><span class="glow"><br></span>
</li>n";
        fwrite($inF,$result);
       }
}
fwrite($inF,"");
closedir($folder);
fclose($inF);

Answer 1

pathinfo()很好，但我认为在这种情况下，您可以使用strrpos()。我不确定你想用$imagename做什么，但我把它留给你。以下是您可以使用代码来比较基本文件名的方法：

// ...
$folder = opendir($path[0]);
while( $file = readdir($folder) ) {
       if (($file != '.')&&($file != '..')&&($file != 'index.htm')) {
            $folder2 = opendir($path[1]);
            $imagename ='';
            $fileBaseName = substr($file,0,strrpos($file,'.'));
            while( $file2 = readdir($folder2) ) {
                $file2BaseName = substr($file2,0,strrpos($file2,'.'));
                if ($file2BaseName == $fileBaseName){
                    $imagename = $file2;
                }
            }
            closedir($folder2);
        $result="<li class="ui-state-default ui-corner-top ui-tabs-selected ui-state-active">n<a href="$file">n$file2n</a><span class="glow"><br></span>
</li>n";
        fwrite($inF,$result);
       }
}

我希望这能有所帮助！