异步Web请求在WCF中不起作用

Question

我正在使用第三方api添加日志api调用，我想将此api异步呼叫以不影响主api调用的时间安排，而且此过程也很低(甚至API结果(不会使用。(

我尝试了以下代码，但对我来说似乎不起作用：

string strLogURL = "www.example.com";
var httpWebRequest = (HttpWebRequest)WebRequest.Create(strLogURL);
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
    string json = new JavaScriptSerializer().Serialize(objAPILog);            
    streamWriter.Write(json);
    streamWriter.Flush();
    streamWriter.Close();
}
httpWebRequest.BeginGetResponse(new AsyncCallback(FinishWebRequest), httpWebRequest);

任何人都可以知道如何从WCF异步调用API？

Answer 1

您可以创建这样的方法：

private static T Call<T>(string url, string body, int timeOut = 60)
{
    var contentBytes = Encoding.UTF8.GetBytes(body);
    var request = (HttpWebRequest)WebRequest.Create(url);
    request.Timeout = timeOut * 1000;
    request.ContentLength = contentBytes.Length;
    request.Method = "DELETE";
    request.ContentType = @"application/json";
    using (var requestWritter = request.GetRequestStream())
        requestWritter.Write(contentBytes, 0, (int)request.ContentLength);
    var responseString = string.Empty;
    var webResponse = (HttpWebResponse)request.GetResponse();
    var responseStream = webResponse.GetResponseStream();
    using (var reader = new StreamReader(responseStream))
    {
        reader.BaseStream.ReadTimeout = timeOut * 1000;
        responseString = reader.ReadToEnd();
    }
    return JsonConvert.DeserializeObject<T>(responseString);
}

然后，您可以像这样称呼它：

    Task.Run(() => Call<dynamic>("www.example.com", "body"));

Answer 2

如果您要寻找的是异步，那么您可以通过将HttpClient与async/await一起实现。然后，您可以开火＆amp;忘记或确保在离开通话前已经完成。

public void DoSomeWork()
{
    PerformWebWork("http://example.com", new object());
    // Perform other work
    // Forget webWork Task
    // Finish
}
public async Task DoSomeWorkAsync()
{
    Task webWorkTask = PerformWebWork("http://example.com", new object());
    // Perform other work
    // Ensure webWorkTask finished
    await webWorkTask;
    // Finish
}
public async Task PerformWebWork(string url, object objAPILog)
{
    string serializedContent = new JavaScriptSerializer().Serialize(objAPILog);
    using (HttpClient client = new HttpClient())
    {
        StringContent content = new StringContent(serializedContent);
        HttpResponseMessage postResponse = await client.PostAsync(url, content);
    }
}