返回10没有出口-PHP

Question

$ifvalid如果true应返回1。在value为真的情况下，它返回10如果我将其正确返回1。为什么这样？

ajax调用

JS -Calling Ajax

var data = {
   action: "validate_date",
   start_date: 22/2/2017,
   end_date: 22/7/2017,
}; 
$.post(ajaxurl, data, function (response) {
   alert(response)
});

php

<?php
    function validate_date(){
       $start_date = $_POST['start_date'];
       $expiration_date= $_POST['end_date'];
       $ifValid = check_in_range($start_date, $expiration_date);
       echo  $ifValid; //returns 10
       echo  $ifValid;exit;  //returns 1
    }
    function check_in_range($start_date, $end_date)
    {
       // Convert to timestamp
       $start_ts = strtotime($start_date);
       $end_ts = strtotime($end_date);
       $timeNow = strtotime("now");
       // Check that user date is between start & end
       return (($timeNow >= $start_ts) && ($timeNow <= $end_ts));
    }
?>

在响应此ajax时，我做alert(response);

Answer 1

您可以设置如下

的功能

function check_in_range($start_date, $end_date)
{
  // Convert to timestamp
  $start_ts = strtotime($start_date);
  $end_ts = strtotime($end_date);
  $timeNow = strtotime("now");
  // Check that user date is between start & end
  if(($timeNow >= $start_ts) && ($timeNow <= $end_ts)){
      return '1'; // OR return '0'; as you want
  }else{
      return '0'; // OR return '1'; as you want
  }
}