对数组中的自定义对象进行排序的任意方法

Question

我有这个数组

var bookTimeArray = [BookTime]()

预订时间类包含以下内容

var time : String = ""
var status : String = ""
var booked_by : String = ""

现在我需要通过查看 BookTime.time 变量对数组 bookTimeArray 进行排序。

时间

变量可以包含从"12AM"到"11PM"的一个时间

对象需要按以下模式排序

["12AM", "1AM", "2AM", "3AM", "4AM", "5AM", "6AM", "7AM", "8AM", "9AM", "10AM", "11AM", "12PM", "1PM", "2PM", "3PM", "4PM", "5PM", "6PM", "7PM", "8PM", "9PM","10PM", "11PM"]

如果 bookTimeArray 有 5 个对象

bookTimeArray[0].time = "10AM"
bookTimeArray[1].time = "6AM"
bookTimeArray[2].time = "9AM"
bookTimeArray[3].time = "6PM"
bookTimeArray[4].time = "9PM"

预期产出

bookTimeArray[0].time = "6AM"
bookTimeArray[1].time = "9AM"
bookTimeArray[2].time = "10AM"
bookTimeArray[3].time = "6PM"
bookTimeArray[4].time = "9PM"

我不知道如何实现这一目标。帮帮我解决:(

Answer 1

你可以这样做：

// First create a DateFormatter object to convert your time strings to Date objects so you can compare between them.
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "ha"
dateFormatter.locale = Locale(identifier: "en_US_POSIX")
// Then you only need to sort the bookTimeArray by *time* property after converting *time* string to a Date object using the dateFormatter that we've created above.
let sortedBooks = bookTimeArray.sorted { dateFormatter.date(from: $0.time)! < dateFormatter.date(from: $1.time)! }

Answer 2

您可以使用

dateFormatter从String属性创建Date对象，然后可以按这些Date对数组进行排序

let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "ha" // format 1AM, 2AM, 12PM, ...
dateFormatter.locale = Locale(identifier: "en_US_POSIX")

排序：

bookTimeArray.sort { bookTime1, bookTime2 in
    guard let date1 = dateFormatter.date(from: bookTime1.time), let date2 = dateFormatter.date(from: bookTime2.time) else { return false }
    return date1 < date2
}

Answer 3

希望这会有所帮助：

// Custom models array   
 let dataArray = [Class(fileID:1),Class(fileID:2),Class(fileID:3)]
// here is sorting code
    dataArray.sorted({ $0.fileID > $1.fileID })