我目前正在研究一个 Gui，它一直计数到达到给定的输入数字。应该可以在计数期间停止 while-循环，并使用按钮再次重新启动它，而无需结束主 Gui 线程。这已经有效，但前提是目标计数数字在线程工作函数中是固定的，例如 n = 10 -> 计数为 10，并且不能在不关闭 Gui 的情况下更改为 20 或任何其他数字并更改主代码中的数字。我想对数字输入使用行编辑并将所需的目标数字发送到线程，以便在我开始计数时它最多计数到给定的数字。但是，当启动 Gui 时(在实现发送和获取输入值通常需要的信号之后(在行编辑中键入数字并按下开始按钮，我得到一个 TypeError，指出"装饰的插槽没有与 started(( 兼容的签名"("已启动"应该连接线程和工作线程函数(。有没有人偶然知道我在哪里犯了错误或必须更改某些内容和/或是否有针对此错误的解决方法？
我很绝望(我一直在尝试解决这个问题很长一段时间，但在网上找不到任何提示......(非常感谢任何帮助！最好的问候和感谢！
这是带有注释的完整代码：
import sys
import time
from PyQt5.QtWidgets import QPushButton, QMainWindow, QApplication, QLineEdit
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
class Worker(QObject):
finished = pyqtSignal() # signal out to main thread to alert it that work is completed
def __init__(self):
super(Worker, self).__init__()
self.working = True # flag to control our loop
@pyqtSlot(int) # should take the sended integer n from signal...
def work(self, n):
s = 0
while self.working:
if s != n: # count until input integer is reached (doesn't work so far)
print(s)
s += 1
time.sleep(0.5)
self.finished.emit() # alert gui that the loop stopped
class Window(QMainWindow):
sendnumber = pyqtSignal(int) # send signal (this is how it is usually done...?)
def __init__(self):
super(Window, self).__init__()
self.setGeometry(50, 50, 200, 250)
self.setWindowTitle("Program")
self.inputnumber=QLineEdit(self, placeholderText="number")
self.inputnumber.resize(self.inputnumber.minimumSizeHint())
self.inputnumber.move(50, 50)
self.startbtn = QPushButton("Start", self)
self.startbtn.resize(self.startbtn.minimumSizeHint())
self.startbtn.move(50, 100)
self.stopbtn = QPushButton("Stop", self)
self.stopbtn.resize(self.stopbtn.minimumSizeHint())
self.stopbtn.move(50, 150)
self.thread = None
self.worker = None
self.startbtn.clicked.connect(self.start_loop)
def start_loop(self):
self.thread = QThread() # a new thread to run the background tasks in
self.worker = Worker() # a new worker to perform those tasks
self.worker.moveToThread(self.thread) # move the worker into the thread, do this first before connecting the signals
self.thread.started.connect(self.worker.work) # begin worker object loop when the thread starts running
self.sendnumber.connect(self.worker.work) # connect input number to worker in thread
# this doesn't work so far and gives a TypeError!
self.stopbtn.clicked.connect(self.stop_loop) # stop the loop on the stop button click
self.worker.finished.connect(self.loop_finished) # do something in the gui when the worker loop ends
self.worker.finished.connect(self.thread.quit) # tell the thread it's time to stop running
self.worker.finished.connect(self.worker.deleteLater) # have worker mark itself for deletion
self.thread.finished.connect(self.thread.deleteLater) # have thread mark itself for deletion
# make sure those last two are connected to themselves or you will get random crashes
self.thread.start()
def stop_loop(self):
self.worker.working = False
# when ready to stop the loop, set the working flag to false
@pyqtSlot() # as far as I know you need this Slot to send the input to Slot in thread?
def getnumber(self):
try:
n = int(self.inputnumber.text()) # input for the work function in thread
print('Trying number...')
except:
print('Use an integer!')
return
self.sendnumber.emit(n) # emit integer signal
print('Emitting signal to worker...')
def loop_finished(self):
# received a callback from the thread that it's completed
print('Loop finished.')
if __name__ == '__main__':
def run():
app = QApplication(sys.argv)
gui = Window()
gui.show()
app.exec_()
run()
这是显示错误的控制台输出：
Traceback (most recent call last):
File "C:/Users/***/WhileLoopInterruptTest2.py", line 63, in start_loop
self.thread.started.connect(self.worker.work)
TypeError: decorated slot has no signature compatible with started()
这就是所有错误所说的，必须关闭 Gui。 我正在使用Python 3.6.1，Spyder 3.3.1，PyQt5.9。
替换此行：
self.thread.started.connect(self.worker.work)
有了这个：
self.thread.started.connect(lambda: self.worker.work(10))
您可以将10替换为文本框中的值。请记住先将其转换为int。
查看本文以获取更详细的说明。