假设我的集合中有以下文档:
{
"Tag-1": "val-1",
"Tag-2":
{
"S_Tag-1": {"SS_Tag_1":"SS_Tag_Val_1","SS_Tag_2":"SS_Tag_Val_2"},
"S_Tag-2": {"SS_Tag_1":"SS_Tag_Val_3","SS_Tag_2":"SS_Tag_Val_3"},
"S_Tag-3": {"SS_Tag_1":"SS_Tag_Val_1","SS_Tag_2":"SS_Tag_Val_2"},
}
}
现在我想要得到S_Tag
的所有子代,其子代值为"SS_Tag_Val_1"
预期输出:
"S_Tag-1": {"SS_Tag_1":"SS_Tag_Val_1","SS_Tag_2":"SS_Tag_Val_2"}
"S_Tag-3": {"SS_Tag_1":"SS_Tag_Val_1","SS_Tag_2":"SS_Tag_Val_2"}
如何在MongoDB中实现?
提前感谢!
文档结构可以更好地为您提供其他选项。但你需要JavaScript处理来过滤和匹配所以最好的方法是mapReduce:
db.collection.mapReduce(
function () {
var obj = {};
var count = 0;
for ( var t in this["Tag-2"] ) {
for ( var k in this["Tag-2"][t] ) {
if ( this["Tag-2"][t][k] === "SS_Tag_Val_1" ) {
obj[t] = this["Tag-2"][t];
count++;
break;
}
}
}
if ( count != 0 )
emit( this._id, obj );
},
function(){},
{ "out": { "inline": 1 } }
)
给你:
"results" : [
{
"_id" : ObjectId("538ea58506bfa12156d3041a"),
"value" : {
"S_Tag-1" : {
"SS_Tag_1" : "SS_Tag_Val_1",
"SS_Tag_2" : "SS_Tag_Val_2"
},
"S_Tag-3" : {
"SS_Tag_1" : "SS_Tag_Val_1",
"SS_Tag_2" : "SS_Tag_Val_2"
}
}
}
]
所以在实际情况中你需要它的一些变体你可以遍历你的对象结构。由于路径设置,这不是最好的查询。考虑使用数组来简化查询。