我有一个简单的测试:
function it_should_return_error_response_exception(Client $httpClient,CommandInterface $commandInterface)
{
$httpClient->setDefaultOption('auth', array('api','api_pass', 'Basic'))
->shouldBeCalled();
$httpClient->getCommand('search', array('api_key' => 'ehudwqukhjda'))
->shouldBeCalled()
->willReturn($commandInterface);
$httpClient->execute($commandInterface)
->shouldBeCalled()
->willThrow(new BadResponseException('???', new Request('POST', 'http://vatteloapesca')));
$this->shouldThrow('AcmeExceptionErrorResponseException')
->during('runCommand', array('search', array('api_key' => 'ehudwqukhjda')));
}
这是我想要的代码test:
try{
$result = $this->guzzleClient->execute($command);
} catch (BadResponseException $e) {
ErrorHandler::processError($e);
}
return $result;
错误处理程序类,它已经测试过,并将返回一个扩展'AcmeExceptionErrorResponseException'的类。问题是,如何模拟从guzzle客户端返回的异常??
我试过使用预言的willTrhow和ThrowPromises https://github.com/phpspec/prophecy
我的错误是什么?
我的意思是,用这个代码:
$httpClient->execute($commandInterface)
->shouldBeCalled()
->willThrow(new BadResponseException('???', new Request('POST', 'http://vatteloapesca')));
'runCommand'(测试的函数)它将返回BadResponseException,但它没有被我的代码捕获。
你可以这样做:
在spec的顶部使用Exception:
use CRMPiccoBundleExceptionImageImportDirectoryUnavailableException;
$this->shouldThrow(ImageImportDirectoryUnavailableException::class)
->during('importImageAssets', [$imageImportPath]);
…并从你的代码中抛出它:
public function importImageAssets($importDirectory)
{
$filesystem = new Filesystem();
if (false === $filesystem->exists($importDirectory)) {
throw new ImportDirectoryUnavailableException();
}
// ...
}