Lua 代码否则如果不起作用

Question

这就是接受用户的输入并使用该特定文本进行搜索。

玩string.gsub.

io.write("ENTER ANY STORY :-D ")
story=io.read()
io.write("t OKAY!, THAT'S NICE :-D  ")
io.write("t DO YOU WANT TO REPLACE ANY TEXT:?  ")
accept=io.read()
if accept=="YES" or "yes" then
io.write("t WHICH TEXT TO REPLAE?  ")
replace=io.read()
--HERE IS THE REPLACING TEXT
io.write("t WITH WHAT:?   ")
with=io.read()
result=string.gsub(story,replace,with)
print("t THE REPLACED TEXT IS: ",result)
elseif accept=="NO" or "no" then
print(result)
end

错误：elseif循环不起作用！！

Answer 1

==和or的工作方式类似于数学运算符，因为它们一次被计算一个，首先计算==。如果accept'no'，accept=="YES" or "yes"将像这样计算：

(accept == "YES") or "yes"
('no' == "YES") or "yes"
false or "yes"
"yes"

在 Lua 中，除nil和false之外的所有值都是真实的，因此您的if块将始终运行而不是elseif块。

正如评论中所说，accept:upper()=="YES"会修复它。accept:upper()返回一个字符串，其中accept的所有字母都转换为大写，因此您只需将其与一个值进行比较。

Answer 2

试试这个。

io.write("ENTER ANY STORY :-D ")
story=io.read()
io.write("t OKAY!, THAT'S NICE :-D  ")
io.write("t DO YOU WANT TO REPLACE ANY TEXT:?  ")
accept=io.read()
if accept=="YES" or accept == "yes" then
io.write("t WHICH TEXT TO REPLAE?  ")
replace=io.read()
--HERE IS THE REPLACING TEXT
io.write("t WITH WHAT:?   ")
with=io.read()
result=string.gsub(story,replace,with)
print("t THE REPLACED TEXT IS: ",result)
elseif accept=="NO" or accept == "no" then
print(result)
end