Javascript 将键值字符串解析为 JSON

Question

我目前正在尝试创建一个UDF，以根据网络流量将键值对字符串拆分为JSON。

我已经设法输出了一个 JSON 对象，但我希望能够根据购买或查看的产品数量根据键的索引号动态添加嵌套项目。

仅查看产品时，字符串中始终只有一个产品。只有当它是一笔交易时，它才不止一个，但我认为最好符合 json 的结构，然后根据交易 ID 的存在来识别购买或视图。例如：

购买的项目：

sessionid=12345&transactionid=555555&product1=apples&productprice1=12&product1qty=1&product2=pears&productprice2=23&product2qty=3&transactionamount=58

输出应如下所示：

[
{
"sessionid":12345,
"transactionid":555555,
"transactionamount":58
},
[
{
"productline":1,
"product":"apples",
"productprice":12,
"productqty":1
},
{
"productline":2,
"product":"pears",
"productprice":23,
"productqty":2
}
]
]

查看的项目：

会话 ID=12345&产品1=苹果&产品价格1=12&产品1qty=1&产品2=梨&产品价格2=23&产品2qty=3

[
{
"sessionid":12345,
"transactionid":0,
"transactionamount":0
},
[
{
"productline":1,
"product":"apples",
"productprice":12,
"productqty":1
}
]
]

结果我将能够从 JSON 解析为 SQL 表中的符合表。

到目前为止，我尝试的只是解析字符串，但在 SQL 中创建表并不理想，因为购买次数可能会有所不同：

var string = "sessionid=12345&transactionid=555555&product1=apples&productprice1=12&product1qty=1&product2=pears&productprice2=23&product2qty=3&transactionamount=58";
function splitstring(queryString) {
var dictionary = {};
if (queryString.indexOf('?') === 0) {
queryString = queryString.substr(1);
}
var parts = queryString.split('&');
for (var i = 0; i < parts.length; i++) {
var p = parts[i];
// Step 2: Split Key/Value pair
var keyValuePair = p.split('=');
var key = keyValuePair[0];
var value = keyValuePair[1];
dec_val = decodeURIComponent(value);
final_value = dec_val.replace(/+/g, ' ');
dictionary[key] = final_value;
}
return (dictionary);
}
console.log(splitstring(string));

提前谢谢!!

Answer 1

感觉这在更好的参数命名约定下会不那么笨拙，但这是我的看法......

function parseString(string) {
var string = string || '',
params, param, output, i, l, n, v, k, pk;
params = string.split('&');
output = [{},
[]
];
for (i = 0, l = params.length; i < l; i++) {
param = params[i].split('=');
n = param[0].match(/^product.*?([0-9]+).*/);
v = decodeURIComponent(param[1] || '');
if (n && n[1]) {
k = n[1];
output[1][k] = output[1][k] || {};
output[1][k]['productline'] = k;
pk = n[0].replace(/[0-9]+/, '');
output[1][k][pk] = v;
} else {
output[0][param[0]] = v;
}
}
output[1] = output[1].filter(Boolean);
return output;
}
var string = "sessionid=12345&transactionid=555555&product1=apples&productprice1=12&product1qty=1&product2=pears&productprice2=23&product2qty=3&transactionamount=58";
console.log(parseString(string));

输出：

[
{
"sessionid": "12345",
"transactionid": "555555",
"transactionamount": "58"
},
[{
"productline": "1",
"product": "1",
"productprice": "12"
}, {
"productline": "2",
"product": "3",
"productprice": "23"
}]
]

Answer 2

可能有一个更好的方法可以做到这一点，但我只是在思考时编写代码

var string = "sessionid=12345&transactionid=555555&product1=apples&productprice1=12&product1qty=1&product2=pears&productprice2=23&product2qty=3&transactionamount=58";
function splitstring(queryString) {
var dictionary = {};
if (queryString.indexOf('?') === 0) {
queryString = queryString.substr(1);
}
var parts = queryString.split('&');
for (var i = 0; i < parts.length; i++) {
var p = parts[i];
// Step 2: Split Key/Value pair
var keyValuePair = p.split('=');
var key = keyValuePair[0];
var value = keyValuePair[1];
dec_val = decodeURIComponent(value);
final_value = dec_val.replace(/+/g, ' ');
dictionary[key] = final_value;
}
return (dictionary);
}
function process(obj) {
let i = 1;
const products = [];
while(obj.hasOwnProperty(`product${i}`)) {
products.push({
[`product`]: obj[`product${i}`],
[`productprice`]: obj[`productprice${i}`],
[`productqty`]: obj[`product${i}qty`]
});
delete obj[`product${i}`];
delete obj[`productprice${i}`];
delete obj[`product${i}qty`];
++i;
}
return [obj, products];
}
console.log(process(splitstring(string)));

顺便说一句，如果这是在浏览器中，那么splitstring可以"替换"为

const splitstring = string => Object.fromEntries(new URLSearchParams(string).entries());

var string = "sessionid=12345&transactionid=555555&product1=apples&productprice1=12&product1qty=1&product2=pears&productprice2=23&product2qty=3&transactionamount=58";
function process(string) {
const splitstring = queryString => {
var dictionary = {};
if (queryString.indexOf('?') === 0) {
queryString = queryString.substr(1);
}
var parts = queryString.split('&');
for (var i = 0; i < parts.length; i++) {
var p = parts[i];
// Step 2: Split Key/Value pair
var keyValuePair = p.split('=');
var key = keyValuePair[0];
var value = keyValuePair[1];
dec_val = decodeURIComponent(value);
final_value = dec_val.replace(/+/g, ' ');
dictionary[key] = final_value;
}
return (dictionary);
};
let i = 1;
const obj = splitstring(string);
const products = [];
while (obj.hasOwnProperty(`product${i}`)) {
products.push({
[`product`]: obj[`product${i}`],
[`productprice`]: obj[`productprice${i}`],
[`productqty`]: obj[`product${i}qty`]
});
delete obj[`product${i}`];
delete obj[`productprice${i}`];
delete obj[`product${i}qty`];
++i;
}
return [obj, products];
}
console.log(process(string));