如果要重新生成许多索引，Azure SQL 重新生成索引脚本将失败

Question

我有一个脚本来重建/重新组织索引，如下所示在Azure SQL服务器中。问题是它会导致应用程序挂起，因为所有数据库会话都将从此脚本中获取。它在游标内调用重建sql语句，所以我预计它会一个接一个地重建索引。但似乎所有索引重建都将并行运行，否则没有理由数据库开始挂起并且在此过程中无法建立连接。如果要重建的索引很少，则没问题。当有大约 60 个索引要重建时，问题就开始了。有没有办法强制一个接一个地构建索引？(顺序，而不是并行(。

CREATE PROCEDURE [dbo].[RebuildIndexes]
AS
BEGIN
    SET NOCOUNT ON;
    DECLARE @objectid int;
    DECLARE @indexid int;
    DECLARE @partitioncount bigint;
    DECLARE @schemaname nvarchar(130);
    DECLARE @objectname nvarchar(130);
    DECLARE @indexname nvarchar(250);
    DECLARE @partitionnum bigint;
    DECLARE @partitions bigint;
    DECLARE @frag float;
    DECLARE @command nvarchar(4000);
    -- Conditionally select tables and indexes from the sys.dm_db_index_physical_stats function
    -- and convert object and index IDs to names.
    SELECT
        object_id AS objectid,
        index_id AS indexid,
        partition_number AS partitionnum,
        avg_fragmentation_in_percent AS frag
    INTO #indexes_to_build
    FROM sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL , NULL, 'LIMITED')
    WHERE avg_fragmentation_in_percent > 10.0 AND index_id > 0 and page_count > 200
    ORDER BY avg_fragmentation_in_percent DESC;
    -- Declare the cursor for the list of partitions to be processed.
    DECLARE partitions CURSOR FOR SELECT * FROM #indexes_to_build;
    -- Open the cursor.
    OPEN partitions;
    -- Loop through the partitions.
    WHILE (1=1)
        BEGIN;
            FETCH NEXT
               FROM partitions
               INTO @objectid, @indexid, @partitionnum, @frag;
            IF @@FETCH_STATUS < 0 BREAK;
            SELECT @objectname = QUOTENAME(o.name), @schemaname = QUOTENAME(s.name)
            FROM sys.objects AS o
            JOIN sys.schemas as s ON s.schema_id = o.schema_id
            WHERE o.object_id = @objectid;
            SELECT @indexname = QUOTENAME(name)
            FROM sys.indexes
            WHERE  object_id = @objectid AND index_id = @indexid;
            SELECT @partitioncount = count (*)
            FROM sys.partitions
            WHERE object_id = @objectid AND index_id = @indexid;
    -- 30 is an arbitrary decision point at which to switch between reorganizing and rebuilding.
            IF @frag < 30.0
                SET @command = N'ALTER INDEX ' + @indexname + N' ON ' + @schemaname + N'.' + @objectname + N' REORGANIZE';
            IF @frag >= 30.0
                SET @command = N'ALTER INDEX ' + @indexname + N' ON ' + @schemaname + N'.' + @objectname + N' REBUILD WITH (ONLINE = ON)';
            IF @partitioncount > 1
                SET @command = @command + N' PARTITION=' + CAST(@partitionnum AS nvarchar(10));
            EXEC (@command);
            PRINT N'Executed: ' + @command;
        END;
    -- Close and deallocate the cursor.
    CLOSE partitions;
    DEALLOCATE partitions;
    -- Drop the temporary table.
    DROP TABLE #indexes_to_build;
    COMMIT;
END;

Answer 1

有没有办法强制一个接一个地构建索引？

TSQL 始终按顺序执行。 您的 ALTER INDEX 命令也不例外。

最后COMMIT是问题所在。 如前所述，该过程只会在IMPLICIT_TRANSACTIONS的情况下运行。 在循环后使用 COMMIT，您可以在重建目标索引时在目标索引上累积独占锁 (Sch-M(。 当您处理大量索引时，您将阻止越来越多的其他会话。

你不应该那样做。 相反，不要在每次重新生成索引后使用 IMPLICIT_TRANSACTIONS 或 COMMIT 。 例如：

    IF @partitioncount > 1
        SET @command = @command + N' PARTITION=' + CAST(@partitionnum AS nvarchar(10));
    EXEC (@command);
    PRINT N'Executed: ' + @command;
    COMMIT;

Answer 2

我的建议是使用Ola Hallemgren的存储过程名称Index Optimize，您可以从这里下载。每个人都使用他的脚本来完成索引维护任务。

可以运行如下所示的存储过程：

EXECUTE dbo.IndexOptimize
@Databases = 'mydbnamehere',
@FragmentationLow = NULL,
@FragmentationMedium = 'INDEX_REORGANIZE,INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationHigh = 'INDEX_REBUILD_ONLINE,INDEX_REBUILD_OFFLINE',
@FragmentationLevel1 = 5,
@FragmentationLevel2 = 30,
@UpdateStatistics = 'ALL',
@OnlyModifiedStatistics = 'Y'

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