循环此操作以获取要显示的所有值，而不仅仅是显示最后一个值(邮政编码)

Question

function ViewInput() {
document.getElementById('display').innerHTML = document.getElementById("firstname").value;
document.getElementById('display').innerHTML = document.getElementById("lastname").value;
document.getElementById('display').innerHTML = document.getElementById("shippingaddress").value;
document.getElementById('display').innerHTML = document.getElementById("country").value;
document.getElementById('display').innerHTML = document.getElementById("city").value;
document.getElementById('display').innerHTML = document.getElementById("state").value;
document.getElementById('display').innerHTML = document.getElementById("phonenumber").value;
document.getElementById('display').innerHTML = document.getElementById("cardnumber").value;
document.getElementById('display').innerHTML = document.getElementById("securitycode").value;
document.getElementById('display').innerHTML = document.getElementById("expirationdate").value;
document.getElementById('display').innerHTML = document.getElementById("zipcode").value;

感谢您的任何帮助！

Answer 1

只需附加新内容，不要覆盖它。

function ViewInput() {
var display = document.getElementById('display');
display.innerHTML = document.getElementById("firstname").value;
display.innerHTML += document.getElementById("lastname").value;
display.innerHTML += document.getElementById("shippingaddress").value;
display.innerHTML += document.getElementById("country").value;
display.innerHTML += document.getElementById("city").value;
display.innerHTML += document.getElementById("state").value;
display.innerHTML += document.getElementById("phonenumber").value;
display.innerHTML += document.getElementById("cardnumber").value;
display.innerHTML += document.getElementById("securitycode").value;
display.innerHTML += document.getElementById("expirationdate").value;
display.innerHTML += document.getElementById("zipcode").value;
}