如何识别"类型'列表'<String>不是类型转换中类型'字符串'的子类型"

Question

我知道这个错误是什么，但无法确定是代码的哪一部分导致的。

我如何识别和理解我的代码的哪一部分导致了这种情况？

我已经创建了一些非常基本的单元测试来验证我的fromJson/jsonDecode和toJson/JasonEncode函数，除了在使用嵌套类/列表时使用fromJson之外，其他一切都可以正常工作。

当使用toJson/jsonEncode时，我能够成功地生成以下字符串

{"id":1,"title":"The Hits","songList":[{"id":1,"title":"hello","artist":"me","lyrics":"say stuff","genre":"rock","rank":10,"created":"2020-04-06T22:00:00.000"},{"id":2,"title":"howdy","artist":"you","lyrics":"say no","genre":"hillBilly","rank":9,"created":"2019-04-06T22:00:00.000"},{"id":3,"title":"Ola","artist":"we","lyrics":"say  nothing","genre":"Flapp","rank":2,"created":"2018-04-06T22:00:00.000"}],"created":"2018-04-06T22:00:00.000"}

我不明白为什么fromJson/Dedecode由于强制转换错误而失败。

单元测试

test('Create Setlist including songList from complex json', (){
    Setlist complexSet = Setlist.fromJson(jsonDecode(complexObjectJson));
    print(complexSet);
  });

这是来自Setlist类的Setlist.fromJson工厂方法

factory Setlist.fromJson(dynamic json) {
    if (json['songList'] != null) {
      var songObjsJson = json['songList'] as List;
      List<Song> _songs = songObjsJson.map((songJson) => Song.fromJson(songJson)).toList();
      return Setlist(
        id: json['id'] as int,
        title: json['title'] as String,
        songList: _songs,
        created: ['created'] as String,
      );
    } else {
      return Setlist(
        id: json['id'] as int,
        title: json['title'] as String,
        created: ['created'] as String,
      );
    }
  }

歌曲类

class Song {
  final int id;
  final String title;
  final String artist;
  final String lyrics;
  final String genre;
  final int rank;
  final String created;
  Song(
      {this.id,
      this.title,
      this.artist,
      this.lyrics,
      this.genre,
      this.rank,
      this.created});
  Map toJson() => {
        'id': id,
        'title': title,
        'artist': artist,
        'lyrics': lyrics,
        'genre': genre,
        'rank': rank,
        'created': created,
      };
  factory Song.fromJson(dynamic json) {
    return Song(
        id: json['id'] as int,
        title: json['title'] as String,
        artist: json['artist'] as String,
        lyrics: json['lyrics'] as String,
        genre: json['genre'] as String,
        rank: json['rank'] as int,
        created: json['created'] as String);
  }
  @override
  String toString() {
    return 'Song{id: $id, '
        'title: $title, '
        'artist: $artist, '
        'lyrics: $lyrics, '
        'genre: $genre, '
        'rank: $rank, '
        'created: $created}';
  }
}

Answer 1

您的song类似乎是错误的，

试试这个

class Song {
    int id;
    String title;
    List<SongList> songList;
    DateTime created;
    Song({
        this.id,
        this.title,
        this.songList,
        this.created,
    });
    factory Song.fromJson(Map<String, dynamic> json) => Song(
        id: json["id"],
        title: json["title"],
        songList: List<SongList>.from(json["songList"].map((x) => SongList.fromJson(x))),
        created: DateTime.parse(json["created"]),
    );
    Map<String, dynamic> toJson() => {
        "id": id,
        "title": title,
        "songList": List<dynamic>.from(songList.map((x) => x.toJson())),
        "created": created.toIso8601String(),
    };
}
class SongList {
    int id;
    String title;
    String artist;
    String lyrics;
    String genre;
    int rank;
    DateTime created;
    SongList({
        this.id,
        this.title,
        this.artist,
        this.lyrics,
        this.genre,
        this.rank,
        this.created,
    });
    factory SongList.fromJson(Map<String, dynamic> json) => SongList(
        id: json["id"],
        title: json["title"],
        artist: json["artist"],
        lyrics: json["lyrics"],
        genre: json["genre"],
        rank: json["rank"],
        created: DateTime.parse(json["created"]),
    );
    Map<String, dynamic> toJson() => {
        "id": id,
        "title": title,
        "artist": artist,
        "lyrics": lyrics,
        "genre": genre,
        "rank": rank,
        "created": created.toIso8601String(),
    };
}

Answer 2

我刚刚使用您提供的json创建了一个示例

以下是json:

{
    "id": 1,
    "title": "The Hits",
    "songList": [{
        "id": 1,
        "title": "hello",
        "artist": "me",
        "lyrics": "say stuff",
        "genre": "rock",
        "rank": 10,
        "created": "2020-04-06T22:00:00.000"
    }, {
        "id": 2,
        "title": "howdy",
        "artist": "you",
        "lyrics": "say no",
        "genre": "hillBilly",
        "rank": 9,
        "created": "2019-04-06T22:00:00.000"
    }, {
        "id": 3,
        "title": "Ola",
        "artist": "we",
        "lyrics": "say  nothing",
        "genre": "Flapp",
        "rank": 2,
        "created": "2018-04-06T22:00:00.000"
    }],
    "created": "2018-04-06T22:00:00.000"
}

稍后是您提供的json的模式：

// To parse this JSON data, do
//
//     final song = songFromJson(jsonString);
import 'dart:convert';
Song songFromJson(String str) => Song.fromJson(json.decode(str));
String songToJson(Song data) => json.encode(data.toJson());
class Song {
    int id;
    String title;
    List<SongList> songList;
    DateTime created;
    Song({
        this.id,
        this.title,
        this.songList,
        this.created,
    });
    factory Song.fromJson(Map<String, dynamic> json) => Song(
        id: json["id"],
        title: json["title"],
        songList: List<SongList>.from(json["songList"].map((x) => SongList.fromJson(x))),
        created: DateTime.parse(json["created"]),
    );
    Map<String, dynamic> toJson() => {
        "id": id,
        "title": title,
        "songList": List<dynamic>.from(songList.map((x) => x.toJson())),
        "created": created.toIso8601String(),
    };
}
class SongList {
    int id;
    String title;
    String artist;
    String lyrics;
    String genre;
    int rank;
    DateTime created;
    SongList({
        this.id,
        this.title,
        this.artist,
        this.lyrics,
        this.genre,
        this.rank,
        this.created,
    });
    factory SongList.fromJson(Map<String, dynamic> json) => SongList(
        id: json["id"],
        title: json["title"],
        artist: json["artist"],
        lyrics: json["lyrics"],
        genre: json["genre"],
        rank: json["rank"],
        created: DateTime.parse(json["created"]),
    );
    Map<String, dynamic> toJson() => {
        "id": id,
        "title": title,
        "artist": artist,
        "lyrics": lyrics,
        "genre": genre,
        "rank": rank,
        "created": created.toIso8601String(),
    };
}

这是从json:中呈现ui的主文件

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'dummy.dart';
void main() => runApp(MyApp());
class MyApp extends StatefulWidget {
  MyApp({Key key}) : super(key: key);
  _MyAppState createState() => _MyAppState();
}
class _MyAppState extends State<MyApp> {
  List<SongList> songList = List();
  bool _isLoading = false;
  @override
  void initState() {
    super.initState();
    loadYourData();
  }
  Future<String> loadFromAssets() async {
    return await rootBundle.loadString('json/parse.json');
  }
  loadYourData() async {
    setState(() {
      _isLoading = true;
    });
    String jsonString = await loadFromAssets();
    final song = songFromJson(jsonString);
    // here you get the complete object
    songList = song.songList;
    setState(() {
      _isLoading = false;
    });
  }
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      home: Scaffold(
        body: Container(
          child: _isLoading
              ? CircularProgressIndicator()
              : ListView.builder(
                  itemCount: songList.length,
                  itemBuilder: (BuildContext context, int index) {
                    return Card(
                      child: Column(
                        children: <Widget>[
                          Text(songList[index].artist),
                          Text(songList[index].genre),
                          Text(songList[index].id.toString()),
                          Text(songList[index].title)
                        ],
                      ),
                    );
                  },
                ),
        ),
      ),
    );
  }
}

如果有效，请告诉我。