我有一个具有持久DateTime字段的模型类,该字段仅通过瞬态属性,String date;
和String time;
的getter/setter进行交互。执行一些非常特殊的格式化来创建DateTime对象,该对象将在需要时持久化或检索。
问题是,当我的模型从yaml文件加载时,time
字段的setter接收到一个字符串值,该值根本不对应于我的项目/代码中的任何内容。
这是只有相关成员的类:
package models;
import javax.persistence.*;
import org.hibernate.annotations.*;
import org.joda.time.*;
import org.joda.time.format.*;
import play.db.jpa.*;
@javax.persistence.Entity
public class Booking extends Model {
@Column
@Type(type = "org.joda.time.contrib.hibernate.PersistentDateTime")
public DateTime datetime;
public Integer duration;
@Transient
public String date;
@Transient
public String time;
//default constructor called by play's model loader that sets default values that are required for the getters and setters to work.
public Booking() {
DateTimeFormatter fmt = DateTimeFormat.forPattern("'ISO8601':yyyy-MM-dd'T'HH:mm:ssZ");
this.datetime = fmt.parseDateTime("ISO8601:1970-01-01T00:00:00+0200");
//this.datetime = fmt.parseDateTime(this.date+"T"+this.time);
}
public void setDate(String dateStr) {
this.date = dateStr;
if (dateStr.contains("ISO")) {
DateTimeFormatter dt = DateTimeFormat.forPattern("'ISO8601':yyyy-MM-dd'T'HH:mm:ssZ");
DateTime tmp = dt.parseDateTime(dateStr);
this.datetime = toDateTime(tmp.toString("yyyy-MM-dd"), getTime());
} else {
this.datetime = toDateTime(dateStr, getTime());
}
}
public void setTime(String timeStr) {
this.time = timeStr; //timeStr = "780" for some reason?!
if (timeStr.contains("ISO")) {
DateTimeFormatter dt = DateTimeFormat.forPattern("'ISO8601':yyyy-MM-dd'T'HH:mm:ssZ");
DateTime tmp = dt.parseDateTime(timeStr);
this.datetime = toDateTime(getDate(), tmp.toString("HH:mm"));
}
this.datetime = toDateTime(getDate(), timeStr);
}
public String getDate() {
DateTimeFormatter format = DateTimeFormat.forPattern("yyyy-MM-dd");
return this.datetime.toString(format);
}
public String getTime() {
DateTimeFormatter format = DateTimeFormat.forPattern("HH:mm");
return this.datetime.toString(format);
}
private DateTime toDateTime(String dateStr, String timeStr) {
DateTimeFormatter fmt = ISODateTimeFormat.dateHourMinute();
DateTime dt = fmt.parseDateTime(dateStr + "T" + timeStr);
return dt;
}
当我运行调试器时,setTime第一次调用时收到的timeStr
参数是"780"
。在我的yaml文件中没有这样的值,因为模型是这样注入的:
Booking(bobBooking):
date: 2011-09-16
time: 13:00
duration: 30
headcount: 10
room: b
user: bob
description: Bob's Booking.
省略附加字段
尝试在yaml文件中使用引号表示时间值。使用SnakeYAML解析器(这是Play中的默认值)解析冒号字段时可能会出现一些问题
YAML 1.1将13:00
定义为十六进制值(这不是您所期望的)
使用单引号或双引号指定字符串值。("13","13")