如何在两种风格的公钥格式之间转换,一种"BEGIN RSA PUBLIC KEY",另一种是"BEGIN PUBLIC KEY"



如何在两种公钥格式之间进行转换?一种格式是:

-----BEGIN PUBLIC KEY-----
...
-----END PUBLIC KEY-----

另一种格式是:

-----BEGIN RSA PUBLIC KEY-----
...
-----END RSA PUBLIC KEY-----
例如,我生成id_rsa/id_rsa。使用ssh-keygen命令发布对我使用以下命令从id_rsa中计算出公钥:

openssl rsa -in id_rsa -pubout -out pub2 

然后我再次从id_rsa中计算公钥。使用:

发布
ssh-keygen -f id_rsa.pub -e -m pem > pub1

内容为pub1 is:

-----BEGIN RSA PUBLIC KEY-----
MIIBCgKCAQEA61BjmfXGEvWmegnBGSuS+rU9soUg2FnODva32D1AqhwdziwHINFa
D1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBSEVCgJjtHAGZIm5GL/KA86KDp/CwDFMSw
luowcXwDwoyinmeOY9eKyh6aY72xJh7noLBBq1N0bWi1e2i+83txOCg4yV2oVXhB
o8pYEJ8LT3el6Smxol3C1oFMVdwPgc0vTl25XucMcG/ALE/KNY6pqC2AQ6R2ERlV
gPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeulmCpGSynXNcpZ/06+vofGi/2MlpQZNhH
Ao8eayMp6FcvNucIpUndo1X8dKMv3Y26ZQIDAQAB
-----END RSA PUBLIC KEY-----

, pub2的内容为:

-----BEGIN PUBLIC KEY-----
MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEA61BjmfXGEvWmegnBGSuS
+rU9soUg2FnODva32D1AqhwdziwHINFaD1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBS
EVCgJjtHAGZIm5GL/KA86KDp/CwDFMSwluowcXwDwoyinmeOY9eKyh6aY72xJh7n
oLBBq1N0bWi1e2i+83txOCg4yV2oVXhBo8pYEJ8LT3el6Smxol3C1oFMVdwPgc0v
Tl25XucMcG/ALE/KNY6pqC2AQ6R2ERlVgPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeu
lmCpGSynXNcpZ/06+vofGi/2MlpQZNhHAo8eayMp6FcvNucIpUndo1X8dKMv3Y26
ZQIDAQAB
-----END PUBLIC KEY-----

根据我的理解,pub1和pub2包含相同的公钥信息,但它们的格式不同,我想知道我如何在两种格式之间转换?谁能给我简单介绍一下这两种格式?

我想帮助解释一下这里发生了什么。

RSA公钥由两个数字组成:

  • 模数(例如2,048位数)
  • 指数(通常为65,537)

以您的RSA公钥为例,这两个数字是:

  • 模量:297056429939040947991047334197581225628107021573849359042679698093131908015712695688944173317630555849768647118986535684992447654339728777985990170679511111819558063246667855023730127805401069042322764200545883378826983730553730138478384327116513143842816383440639376515039682874046227217032079079790098143158087443017552531393264852461292775129262080851633535934010704122673年,027067442627059982393297716922243940155855127430302323883824137412883916794359982603439112095116831297809626059569444750808699678211904501083183234323797142810155862553705570600021649944369726123996534870137000784980673984909570977377882585701
  • 指数
  • : 65537

那么问题就变成了我们如何在计算机中存储这些数字。首先将两者转换为十六进制:

  • 模量:EB506399F5C612F5A67A09C1192B92FAB53DB28520D859CE0EF6B7D83D40AA1C1DCE2C0720D15A0F531595CAD81BA5D129F91CC6769719F1435872C4BCD0521150A0263B470066489B918BFCA03CE8A0E9FC2C0314C4B096EA30717C03C28CA29E678E63D78ACA1E9A63BDB1261EE7A0B041AB53746D68B57B68BEF37B71382838C95DA8557841A3CA58109F0B4F77A5E929B1A25DC2D6814C55DC0F81CD2F4E5DB95EE70C706FC02C4FCA358EA9A82D8043A47611195580F89458E3DAB5592DEFE06CDE1E516A6C61ED78C13977AE9660A9192CA75CD72967FD3AFAFA1F1A2FF6325A5064D847028F1E6B2329E8572F36E708A549DDA355FC74A32FDD8DBA65
  • 指数
  • : 010001

RSA发明了第一种格式

RSA首先发明了一种格式:

RSAPublicKey ::= SEQUENCE {
modulus           INTEGER,  -- n
publicExponent    INTEGER   -- e
}

他们选择使用ASN.1二进制编码标准的DER风格来表示这两个数字[1]:

SEQUENCE (2 elements)
INTEGER (2048 bit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
INTEGER (24 bit): 010001

ASN.1中的最终二进制编码为:

30 82 01 0A      ;sequence (0x10A bytes long)
02 82 01 01   ;integer (0x101 bytes long)
00 EB506399F5C612F5A67A09C1192B92FAB53DB28520D859CE0EF6B7D83D40AA1C1DCE2C0720D15A0F531595CAD81BA5D129F91CC6769719F1435872C4BCD0521150A0263B470066489B918BFCA03CE8A0E9FC2C0314C4B096EA30717C03C28CA29E678E63D78ACA1E9A63BDB1261EE7A0B041AB53746D68B57B68BEF37B71382838C95DA8557841A3CA58109F0B4F77A5E929B1A25DC2D6814C55DC0F81CD2F4E5DB95EE70C706FC02C4FCA358EA9A82D8043A47611195580F89458E3DAB5592DEFE06CDE1E516A6C61ED78C13977AE9660A9192CA75CD72967FD3AFAFA1F1A2FF6325A5064D847028F1E6B2329E8572F36E708A549DDA355FC74A32FDD8DBA65
02 03         ;integer (3 bytes long)
010001

如果你把这些字节放在一起并进行Base64编码,你会得到:

MIIBCgKCAQEA61BjmfXGEvWmegnBGSuS+rU9soUg2FnODva32D1AqhwdziwHINFa
D1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBSEVCgJjtHAGZIm5GL/KA86KDp/CwDFMSw
luowcXwDwoyinmeOY9eKyh6aY72xJh7noLBBq1N0bWi1e2i+83txOCg4yV2oVXhB
o8pYEJ8LT3el6Smxol3C1oFMVdwPgc0vTl25XucMcG/ALE/KNY6pqC2AQ6R2ERlV
gPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeulmCpGSynXNcpZ/06+vofGi/2MlpQZNhH
Ao8eayMp6FcvNucIpUndo1X8dKMv3Y26ZQIDAQAB

RSA实验室然后说添加标题和结尾:

-----BEGIN RSA PUBLIC KEY-----
MIIBCgKCAQEA61BjmfXGEvWmegnBGSuS+rU9soUg2FnODva32D1AqhwdziwHINFa
D1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBSEVCgJjtHAGZIm5GL/KA86KDp/CwDFMSw
luowcXwDwoyinmeOY9eKyh6aY72xJh7noLBBq1N0bWi1e2i+83txOCg4yV2oVXhB
o8pYEJ8LT3el6Smxol3C1oFMVdwPgc0vTl25XucMcG/ALE/KNY6pqC2AQ6R2ERlV
gPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeulmCpGSynXNcpZ/06+vofGi/2MlpQZNhH
Ao8eayMp6FcvNucIpUndo1X8dKMv3Y26ZQIDAQAB
-----END RSA PUBLIC KEY-----

五个连字符和单词BEGIN RSA PUBLIC KEY。这是您的PEM DER ASN.1 pkcs# 1 RSA公钥

  • PEM:base64的同义词
  • DER: ASN.1编码的一种风格
  • ASN。1:使用的二进制编码方案
  • pkcs# 1:规定将公钥表示为由模数后跟指数组成的结构的正式规范
  • RSA公钥:正在使用的公钥算法

不只是RSA

之后,出现了其他形式的公钥加密:

  • diffie - hellman
  • <
  • Ellicptic曲线/gh>

当需要创建一个标准来表示的参数时,加密算法,人们采用了很多RSA最初定义的相同思想:

  • 使用ASN.1二进制编码
  • base64它
  • 用五个连字符
  • 括起来
  • BEGIN PUBLIC KEY

而不是使用:

  • -----BEGIN RSA PUBLIC KEY-----
  • -----BEGIN DH PUBLIC KEY-----
  • -----BEGIN EC PUBLIC KEY-----

他们决定将对象标识符(OID)包含在后面的内容中。对于RSA公钥,即:

  • RSA PKCS # 1:1.2.840.113549.1.1.1

RSA公钥的格式是:

public struct RSAPublicKey {
INTEGER modulus,
INTEGER publicExponent 
}

现在他们创建了SubjectPublicKeyInfo也就是:

public struct SubjectPublicKeyInfo {
AlgorithmIdentifier algorithm,
RSAPublicKey subjectPublicKey
}

在实际DER ASN.1中定义为:

SubjectPublicKeyInfo  ::=  SEQUENCE  {
algorithm  ::=  SEQUENCE  {
algorithm               OBJECT IDENTIFIER, -- 1.2.840.113549.1.1.1 rsaEncryption (PKCS#1 1)
parameters              ANY DEFINED BY algorithm OPTIONAL  },
subjectPublicKey     BIT STRING {
RSAPublicKey ::= SEQUENCE {
modulus            INTEGER,    -- n
publicExponent     INTEGER     -- e
}
}

得到的ASN.1为:

SEQUENCE (2 elements)
SEQUENCE (2 elements)
OBJECT IDENTIFIER 1.2.840.113549.1.1.1
NULL
BIT STRING (1 element)
SEQUENCE (2 elements)
INTEGER (2048 bit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
INTEGER (24 bit): 010001

ASN.1中的最终二进制编码为:

30 82 01 22          ;SEQUENCE (0x122 bytes = 290 bytes)
|  30 0D             ;SEQUENCE (0x0d bytes = 13 bytes) 
|  |  06 09          ;OBJECT IDENTIFIER (0x09 = 9 bytes)
|  |  2A 86 48 86   
|  |  F7 0D 01 01 01 ;hex encoding of 1.2.840.113549.1.1
|  |  05 00          ;NULL (0 bytes)
|  03 82 01 0F 00    ;BIT STRING  (0x10f = 271 bytes)
|  |  30 82 01 0A       ;SEQUENCE (0x10a = 266 bytes)
|  |  |  02 82 01 01    ;INTEGER  (0x101 = 257 bytes)
|  |  |  |  00             ;leading zero of INTEGER
|  |  |  |  EB 50 63 99 F5 C6 12 F5  A6 7A 09 C1 19 2B 92 FA 
|  |  |  |  B5 3D B2 85 20 D8 59 CE  0E F6 B7 D8 3D 40 AA 1C 
|  |  |  |  1D CE 2C 07 20 D1 5A 0F  53 15 95 CA D8 1B A5 D1 
|  |  |  |  29 F9 1C C6 76 97 19 F1  43 58 72 C4 BC D0 52 11 
|  |  |  |  50 A0 26 3B 47 00 66 48  9B 91 8B FC A0 3C E8 A0
|  |  |  |  E9 FC 2C 03 14 C4 B0 96  EA 30 71 7C 03 C2 8C A2  
|  |  |  |  9E 67 8E 63 D7 8A CA 1E  9A 63 BD B1 26 1E E7 A0  
|  |  |  |  B0 41 AB 53 74 6D 68 B5  7B 68 BE F3 7B 71 38 28
|  |  |  |  38 C9 5D A8 55 78 41 A3  CA 58 10 9F 0B 4F 77 A5
|  |  |  |  E9 29 B1 A2 5D C2 D6 81  4C 55 DC 0F 81 CD 2F 4E 
|  |  |  |  5D B9 5E E7 0C 70 6F C0  2C 4F CA 35 8E A9 A8 2D 
|  |  |  |  80 43 A4 76 11 19 55 80  F8 94 58 E3 DA B5 59 2D
|  |  |  |  EF E0 6C DE 1E 51 6A 6C  61 ED 78 C1 39 77 AE 96 
|  |  |  |  60 A9 19 2C A7 5C D7 29  67 FD 3A FA FA 1F 1A 2F 
|  |  |  |  F6 32 5A 50 64 D8 47 02  8F 1E 6B 23 29 E8 57 2F 
|  |  |  |  36 E7 08 A5 49 DD A3 55  FC 74 A3 2F DD 8D BA 65
|  |  |  02 03          ;INTEGER (03 = 3 bytes)
|  |  |  |  010001

和之前一样,你把所有这些字节,Base64编码它们,你结束你的第二个例子:

MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEA61BjmfXGEvWmegnBGSuS
+rU9soUg2FnODva32D1AqhwdziwHINFaD1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBS
EVCgJjtHAGZIm5GL/KA86KDp/CwDFMSwluowcXwDwoyinmeOY9eKyh6aY72xJh7n
oLBBq1N0bWi1e2i+83txOCg4yV2oVXhBo8pYEJ8LT3el6Smxol3C1oFMVdwPgc0v
Tl25XucMcG/ALE/KNY6pqC2AQ6R2ERlVgPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeu
lmCpGSynXNcpZ/06+vofGi/2MlpQZNhHAo8eayMp6FcvNucIpUndo1X8dKMv3Y26
ZQIDAQAB   

添加稍微不同的页眉和页尾,得到:

-----BEGIN PUBLIC KEY-----
MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEA61BjmfXGEvWmegnBGSuS
+rU9soUg2FnODva32D1AqhwdziwHINFaD1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBS
EVCgJjtHAGZIm5GL/KA86KDp/CwDFMSwluowcXwDwoyinmeOY9eKyh6aY72xJh7n
oLBBq1N0bWi1e2i+83txOCg4yV2oVXhBo8pYEJ8LT3el6Smxol3C1oFMVdwPgc0v
Tl25XucMcG/ALE/KNY6pqC2AQ6R2ERlVgPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeu
lmCpGSynXNcpZ/06+vofGi/2MlpQZNhHAo8eayMp6FcvNucIpUndo1X8dKMv3Y26
ZQIDAQAB   
-----END PUBLIC KEY-----

这是你的X.509SubjectPublicKeyInfo/OpenSSL PEM公钥[2] .

要么做好,要么黑掉

现在您知道编码不是魔法,您可以编写解析RSA模数和指数所需的所有部分。或者你可以意识到前24个字节只是在原来的pkcs# 1标准之上添加了新的内容

30 82 01 22          ;SEQUENCE (0x122 bytes = 290 bytes)
|  30 0D             ;SEQUENCE (0x0d bytes = 13 bytes) 
|  |  06 09          ;OBJECT IDENTIFIER (0x09 = 9 bytes)
|  |  2A 86 48 86   
|  |  F7 0D 01 01 01 ;hex encoding of 1.2.840.113549.1.1
|  |  05 00          ;NULL (0 bytes)
|  03 82 01 0F 00    ;BIT STRING  (0x10f = 271 bytes)
|  |  ...

前24个字节是"new"添加的内容:

30 82 01 22 30 0D 06 09 2A 86 48 86 F7 0D 01 01 01 05 00 03 82 01 0F 00

由于运气和运气的巧合:

24字节恰好对应到32个base64编码字符

因为在Base64中:3字节变成了4个字符:

30 82 01  22 30 0D  06 09 2A  86 48 86  F7 0D 01  01 01 05  00 03 82  01 0F 00
______/  ______/  ______/  ______/  ______/  ______/  ______/  ______/
|         |         |         |         |         |         |         |
MIIB      IjAN      Bgkq      hkiG      9w0B      AQEF      AAOC      AQ8A
这意味着如果您使用第二个X.509公钥,前32个字符只对应于新添加的内容:

-----BEGIN PUBLIC KEY-----
MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8A
MIIBCgKCAQEA61BjmfXGEvWmegnBGSuS+rU9soUg2FnODva32D1AqhwdziwHINFa
D1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBSEVCgJjtHAGZIm5GL/KA86KDp/CwDFMSw
luowcXwDwoyinmeOY9eKyh6aY72xJh7noLBBq1N0bWi1e2i+83txOCg4yV2oVXhB
o8pYEJ8LT3el6Smxol3C1oFMVdwPgc0vTl25XucMcG/ALE/KNY6pqC2AQ6R2ERlV
gPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeulmCpGSynXNcpZ/06+vofGi/2MlpQZNhH
Ao8eayMp6FcvNucIpUndo1X8dKMv3Y26ZQIDAQAB
-----END PUBLIC KEY-----

如果删除前32个字符,并将其更改为BEGIN RSA PUBLIC KEY:

-----BEGIN RSA PUBLIC KEY-----
MIIBCgKCAQEA61BjmfXGEvWmegnBGSuS+rU9soUg2FnODva32D1AqhwdziwHINFa
D1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBSEVCgJjtHAGZIm5GL/KA86KDp/CwDFMSw
luowcXwDwoyinmeOY9eKyh6aY72xJh7noLBBq1N0bWi1e2i+83txOCg4yV2oVXhB
o8pYEJ8LT3el6Smxol3C1oFMVdwPgc0vTl25XucMcG/ALE/KNY6pqC2AQ6R2ERlV
gPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeulmCpGSynXNcpZ/06+vofGi/2MlpQZNhH
Ao8eayMp6FcvNucIpUndo1X8dKMv3Y26ZQIDAQAB
-----END RSA PUBLIC KEY-----

你已经得到了你想要的——旧的RSA PUBLIC KEY格式。

我发现这个网站是一个很好的技术解释不同的格式:https://polarssl.org/kb/cryptography/asn1-key-structures-in-der-and-pem

BEGIN RSA PUBLIC KEY"是pkcs# 1,它只能包含RSA密钥。

BEGIN PUBLIC KEY"是一个SPKI(主题公钥信息)密钥(X.509的一部分),它可以包含多种格式。

如果你只是想用命令行转换它们,"openssl rsa"

将SPKI转换为pkcs# 1:

openssl rsa -pubin -in <filename> -RSAPublicKey_out

将pkcs# 1转换为SPKI:

openssl rsa -RSAPublicKey_in -in <filename> -pubout

使用phpseclib,一个纯PHP RSA实现…

<?php
include('Crypt/RSA.php');
$rsa = new Crypt_RSA();
$rsa->loadKey('-----BEGIN PUBLIC KEY-----
MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEA61BjmfXGEvWmegnBGSuS
+rU9soUg2FnODva32D1AqhwdziwHINFaD1MVlcrYG6XRKfkcxnaXGfFDWHLEvNBS
EVCgJjtHAGZIm5GL/KA86KDp/CwDFMSwluowcXwDwoyinmeOY9eKyh6aY72xJh7n
oLBBq1N0bWi1e2i+83txOCg4yV2oVXhBo8pYEJ8LT3el6Smxol3C1oFMVdwPgc0v
Tl25XucMcG/ALE/KNY6pqC2AQ6R2ERlVgPiUWOPatVkt7+Bs3h5Ramxh7XjBOXeu
lmCpGSynXNcpZ/06+vofGi/2MlpQZNhHAo8eayMp6FcvNucIpUndo1X8dKMv3Y26
ZQIDAQAB
-----END PUBLIC KEY-----');
$rsa->setPublicKey();
echo $rsa->getPublicKey(CRYPT_RSA_PUBLIC_FORMAT_PKCS1_RAW);

base64编码的内容看起来是匹配的,即使标头显示BEGIN PUBLIC KEY而不是BEGIN RSA PUBLIC KEY。所以也许只是使用str_replace来解决这个问题,你应该很好!

pub1和pub2之间的唯一区别,除了页眉/页脚之外,是pub2:MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8A中的这个附加字符串。如果你把它去掉,Base 64和pub1中的Base 64是一样的。

根据这个答案,额外的字符串对应于算法标识符。

转换为第三公钥样式(OpenSSH公钥格式):

输入文件:C:mc_pubkey.txt:(inSSH2公钥格式)

---- BEGIN SSH2 PUBLIC KEY ----
Comment: "imported-openssh-key"
AAAAB3NzaC1yc2EAAAADAQABAAABAQCb4oUsXZ51L9DmH3UqSnwOAUr9w6AOZa8b
YH8qsJAhypAjH9YvQteVXXQEY0ybaVE1cmpIKEyC2jmC/jOJ4b7bivlo2hgnLOrj
3FPkDWO2yNNio9RnPXREBx7+iIi9pcaozUmiPMoPxaEyfpGQAvfdFzt+n6+o/hoO
72Zv5RSo0rGr76sLUjx9Mi5TnuI2rT4s9FGMZ9xkgUu3z11UcDhSXqkLEgEEDKBq
bft3VuiQm6Blggzk9tk5L1LAdKM7udhby9dOwXCYPnCKTymYTqi/2FTwKZDj5TJH
V8r6c2Sz/qEdgMkw7RD3ice9m9GYHi2Burgyvjw+Sla+yu0n9sBh
---- END SSH2 PUBLIC KEY ----

将其转换为OpenSSH公钥格式,使用ssh-keygen.exe实用程序。它可能已经在您的计算机上了,因为它是与Git一起打包的。在Powershell中:

> cd C:Program FilesGitusrbin
> .ssh-keygen.exe -i -f "C:mc_pubkey.txt"
ssh-rsa AAAAB3NzaC1yc2EAAAADAQABAAABAQCb4oUsXZ51L9DmH3UqSnwOAUr9w6AOZa8bYH8qsJAhypAjH9YvQteVXXQEY0ybaVE1cmpIKEyC2jmC/jOJ4b7bivlo2hgnLOrj3FPkDWO2yNNio9RnPXREBx7+iIi9pcaozUmiPMoPxaEyfpGQAvfdFzt+n6+o/hoO72Zv5RSo0rGr76sLUjx9Mi5TnuI2rT4s9FGMZ9xkgUu3z11UcDhSXqkLEgEEDKBqbft3VuiQm6Blggzk9tk5L1LAdKM7udhby9dOwXCYPnCKTymYTqi/2FTwKZDj5TJHV8r6c2Sz/qEdgMkw7RD3ice9m9GYHi2Burgyvjw+Sla+yu0n9sBh

这就是你想要的输出!复制粘贴并保存到文件中,就完成了。

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