电话号码表

Question

用c++编写一个简单的电话簿程序，在包含姓名和电话号码列表的文件中查找电话号码。应该提示用户输入名字和姓氏，然后程序输出相应的数字，或者指示该名称不在目录中。在每次查找之后，程序应该询问用户是否要查找另一个数字，然后要么重复该过程，要么退出程序。应该组织文件中的数据，以便每行包含一个名、一个姓和一个电话号码，并用空格分隔。您可以通过关闭文件再打开它来返回文件的开头。

我接不上电话check = strstr(phoneDirectory, name);为了工作STRSTR部分继续给出错误:没有重载函数" STRSTR "的实例与参数列表参数类型匹配。

这里是我的代码副本:

#include <iostream>
#include <string>
#include <fstream>
#include <cstring>
using namespace std;
int arraySize();
 int main()
{
    const int SIZE = arraySize();
    char *phoneDirectory;
    int size=0;
    char name; //name to look for
    char *check = NULL;
    bool find = false;
    phoneDirectory = new char [SIZE];
    ifstream phoneNumbers;
    phoneNumbers.open("phoneNumbers.txt");
    if (!phoneNumbers)
        cout << "Error opening data filen";
    //looping throught the name file
    else
    {
        for (int i = 0; i < SIZE; i++)
        {
            phoneNumbers >> phoneDirectory;
        }
        phoneNumbers.close();       //closes data file
    }
    phoneNumbers.close();
    // Get a name or partial name to search for.
    cout << "Enter a name or partial name to search for: ";
    cin.getline(phoneDirectory, name);
    cout << "nHere are the results of the search: " << endl;
    int entries = 0;
    for (int i = 0; i < size; i++)
    {
        check = strstr(phoneDirectory, name);
        if (check != NULL)
            find = true;
    }
    if (!find) 
        cout << "No matches!" << endl;

    delete [] phoneDirectory;
    return 0;
} 
 int arraySize()
{
    string phoneNum;
    int size = 0;
    ifstream phoneNumbers;      // Input file stream object
    // Open the data file.
    phoneNumbers.open("phoneNumbers.txt");
    if (!phoneNumbers)
        cout << "Error opening data filen";
    //looping throught the name file
    else
    {
        while (getline(phoneNumbers, phoneNum))
        {
            size++;
        }
        phoneNumbers.close();       //closes data file
    }
    return size;
}

Answer 1

您的name变量是char。应该换成char*吗?