你好吗?我希望一切顺利。
所以我试图发送一个urlRequest,我不能通过url传递参数,所以我试图使用URLVariable,但无论我尝试什么,我的php总是得到null。
var request:URLRequest = new URLRequest(SITE_DOMAIN + "/check_login.php");
request.method = URLRequestMethod.POST;
var variables:URLVariables = new URLVariables();
variables.login = emailInput.text;
variables.password = senhaInput.text;
variables.gotogame = "BURACO";
Reflect.setField(variables, "login", emailInput.text);
Reflect.setField(variables, "password", senhaInput.text);
Reflect.setField(variables, "gotogame", "BURACO");
request.data = variables;
request.method = URLRequestMethod.POST;
openfl.Lib.getURL(request);
正如你们所看到的,我试图以两种方式设置变量,但它们都不起作用,我有点不知道该怎么做了,请帮助。
我用这个没有问题:
var request:Http = new Http(SERVER + "actions/layout-builder?random=" + Math.random());
request.addParameter("action", "retrieve");
request.addParameter("layoutId", layoutId);
request.onError = function(msg) {
showSimplePopup("Problem loading layout:nn" + msg);
}
request.onStatus = function(status:Int) {
}
request.onData = function(response) {
response = StringTools.replace(response, "rn", "n");
layoutCode.text = response;
}
request.request(false);