快速传递方法参数结构可解码

Question

，swift 4如何通过方法参数传递 Decodable Struct并在 JSONDecoder()中解析它？错误：

无法用类型的参数列表调用'解码'（可解码， 来自：数据）'

struct JsonRespons: Codable {
    let uid: String
    let msisdn: String
    let APK: String
    let fname: String
    let lname: String
}
struct JsonResponsError: Decodable {
    let uid: String
    let error: String
}
extension UIView {
func phoneAuth(serverApi path:String, jsonStruct:Codable){
    let jsonUrlString = Globals.JOSN_API_URL + path
    guard let url = URL(string: jsonUrlString) else {
        return
    }
    URLSession.shared.dataTask(with: url) { (data, response, err) in
        guard err == nil else {
            return
        }
        guard let data = data else { return }
        do {
            let result = try JSONDecoder().decode(jsonStruct.self, from: data)
            self.handleJsonResult(resalt: result as AnyObject)
        } catch let jsonErr {
            print("Error serializing json:", jsonErr)
        }
    }.resume()
}

    func handleJsonResult(resalt:AnyObject){
        print(resalt)
    }
}

Answer 1

在地标的继承列表中添加代码触发了一个自动符合，该符合满足所有协议要求，可编码和解码：

您可以使用Codable

struct Landmark: Codable {
    var name: String
    var foundingYear: Int
    // Landmark now supports the Codable methods init(from:) and encode(to:), 
    // even though they aren't written as part of its declaration.
}

替代解决方案是

func phoneAuth(serverApi path: String, Completion block: @escaping ((Data) -> ())) {
    URLSession.shared.dataTask(with: URL(string: url)!) { (data, res, err) in
        if let d = data {
            block(d)
        }
    }.resume()
}

调用方法

phoneAuth(serverApi: "yourUrl") { (data) in
    do {
        let result = try JSONDecoder().decode(YourDecodable.self, from: data)
    } catch let jsonErr {
        print("Error serializing json:", jsonErr)
    }
}

Answer 2

您不必将其作为参数传递，您可以像以下那样实现解码

extension UIView {
func phoneAuth(serverApi path:String){
    let jsonUrlString = Globals.JOSN_API_URL + path
    guard let url = URL(string: jsonUrlString) else {
        return
}
URLSession.shared.dataTask(with: url) { (data, response, err) in
    guard err == nil else {
        return
    }
    guard let data = data else { return }
    do {
        let result = try JSONDecoder().decode(JsonRespons.self, from: data)
        self.handleJsonResult(resalt: result as AnyObject)
    } catch let jsonErr {
        print("Error serializing json:", jsonErr)
    }
}.resume()
}