如何测试bcrypt比较功能?

Question

我正在使用这个依赖项：https://www.npmjs.com/package/bcrypt。

我正在尝试测试此功能：

VolunteerSchema.statics.findByCredentials = function (email, password) {
var Volunteer = this
var foundVolunteer
return Volunteer.findOne({email}).then((volunteer) => {
if (volunteer) {
foundVolunteer = volunteer
return bcrypt.compareSync(password, volunteer.password)
} else {
return Promise.reject({error: "Email not found"})
}
}).then((response) => {
if (response) {
console.log("Sending found vol", foundVolunteer)
return Promise.resolve(foundVolunteer)
} else {
return Promise.reject({error: "Incorrect password"})
}
})
};

开玩笑地进行以下测试：

test('Valid credentials', async () => {
var volunteerValid = new Volunteer({
name : 'Test Time',
phone: '1111111111',
password: 'test password',
email : '[e-mail]'
})
await volunteerValid.save()
await expect(Volunteer.findByCredentials('[e-mail]', 'test password')).resolve.toEqual(volunteerValid)
})

我遇到的问题是，即使我在测试中使用了 async-await，该函数也会在测试执行后返回志愿者。

此外，对于此行代码：

console.log("Sending found vol", foundVolunteer)

开玩笑给我错误：测试完成后无法记录。您是否忘记在测试中等待异步内容？

你能帮我弄清楚为什么会这样吗？

Answer 1

您将同步和异步模式混合到您的函数( findByCredentials ( 中，您可以将 findByCredentials 声明为异步并在异步调用时使用 await

VolunteerSchema.statics.findByCredentials = async function (email, password) {
var Volunteer = this
// TODO consider to put a try catch when you call findOne method
let volunteer = await Volunteer.findOne({email})
if(!volunteer){
throw new Error({error: "Email not found"})
}
if (bcrypt.compareSync(password, volunteer.password)) {
console.log("Sending found vol", volunteer)
return volunteer
} else {
throw new Error({error: "Incorrect password"})
}
};