符合结构和数组 Swift 的 JSON 响应

Question

目前，我有一个名为User的结构，它定义了我想从HTTP响应解码的变量。然后，我有一个名为 users 的数组，它将包含响应。如您所见，我在 random8 函数中填充用户，但现在在 random1 函数中我遇到了问题。在 random1 函数中，我只得到 1 个用户而不是 8 个，我正在尝试获取该数据并用该新数据替换其中一个当前用户。我能够在我的代码中成功地做到这一点(通过提取每个值(，但我很确定我没有以标准方式做到这一点。请让我知道是否有更好的方法可以做到这一点。

请记住，random8 是在 viewDidLoad 上调用的，而 random1 会在他们点击特定按钮时稍后发生，因此我将替换一个特定用户索引的数据。

struct User: Decodable {
var id: Int
var first_name: String
var last_name: String
var picture_url: String
var points: Int
var school: String
var grade: Int
}
var users = [User]()
func getRandom8() {
let url = URL(string: "https://somewebsite.com/users/random/eight")
let session = URLSession.shared
let request = NSMutableURLRequest(url: url!)
let preferences = UserDefaults.standard
request.addValue("JWT (preferences.object(forKey: "token") as! String)", forHTTPHeaderField: "Authorization")
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
request.httpMethod = "GET"
let task = session.dataTask(with: request as URLRequest, completionHandler: {
(data, response, error) in
do {
self.users = try JSONDecoder().decode([User].self, from: data!)
DispatchQueue.main.async (
execute: self.loadRandom8
)
} catch {
print("error in getting data")
}
})
task.resume()
}
func getRandom1(index:Int) {
let url = URL(string: "https://somewebsite.com/users/random/one")
let session = URLSession.shared
let request = NSMutableURLRequest(url: url!)
let preferences = UserDefaults.standard
request.addValue("JWT (preferences.object(forKey: "token") as! String)", forHTTPHeaderField: "Authorization")
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
request.httpMethod = "GET"
//write a statement that says if that user is already there, do the call again
let task = session.dataTask(with: request as URLRequest, completionHandler: {
(data, response, error) in
do {
let responseObject = (try? JSONSerialization.jsonObject(with: data!)) as? [String: Any]
print(responseObject)
let indexFirstName = responseObject?.index(forKey: "first_name")
let indexId = responseObject?.index(forKey: "id")
let indexPictureURL = responseObject?.index(forKey: "picture_url")
let indexPoints = responseObject?.index(forKey: "points")
let indexSchool = responseObject?.index(forKey: "school")
let indexGrade = responseObject?.index(forKey: "grade")
let indexLastName = responseObject?.index(forKey: "last_name")
self.users[index].last_name = responseObject![indexLastName!].value as! String
self.users[index].first_name = responseObject![indexFirstName!].value as! String
self.users[index].id = responseObject![indexId!].value as! Int
self.users[index].picture_url = responseObject![indexPictureURL!].value as! String
self.users[index].points = responseObject![indexPoints!].value as! Int
self.users[index].school = responseObject![indexSchool!].value as! String
self.users[index].grade = responseObject![indexGrade!].value as! Int

DispatchQueue.main.async (
execute: self.loadRandom8
)
} catch {
print("error in getting data")
}
})
task.resume()
}

Answer 1

如果没有看到您在random/one请求中获得的 JSON 格式，这有点难说，但您应该能够User使用

let user = try JSONDecoder().decode(User.self, from: data!)

而不是诉诸JSONSerialization

并将数据放入users数组中，请执行users[index] = user