我收到一些关于 Java 中无法访问的代码如何修复它的错误. 我使用Eclipse Neon

Question

我在重新编译时有来自 GitHub 的代码，我在这里收到有关无法访问代码的错误。 这是我的源代码。 这里无法访问的代码是什么意思？ 以及如何解决它？

class z implements Runnable
{
w a;
final OrderClient b;
private static final String[] c;

public z(final OrderClient b, final w a) {
this.b = b;
this.a = a;
}

@Override
public void run() {
try {
this.executeTransaction();
}
catch (Exception exception) {
this.b.onProgress(null, ProgressType.Exception, this.a.e, exception);
}
}

public Order executeTransaction() throws TimeoutException, ConnectException, InterruptedException {
final boolean b = Order.b;
int i = 0;
final boolean b2 = b;
while (i < this.b.TradeTimeout) {
if (this.a.b != null) {
throw this.a.b;
}
if (this.a.d != null) {
return E.b(this.a.d, 0);
}
if (!this.b.QuoteClient.Connected()) {
throw new ConnectException(new Exception(z.c[1]), this.b.Log);
}
try {
Thread.sleep(1L);
}
catch (InterruptedException ex4) {}
++i;
if (b2) {
break;
}
}
final StringBuilder sb = new StringBuilder();
final String[] c = z.c;
throw new TimeoutException(sb.append(c[2]).append(this.b.TradeTimeout).append(c[0]).toString(), this.b.Log);
}

static {
final String[] c2 = new String[3];
int n = 0;
final String s;
final int length = (s = "7{`&Ty}u001dtu000bZ~y}S}u0007]c6wu0006cu0001@p6|u0001ur\7sku0016ru001dZ~y}u0018Yy3u0001tu0018Bn6uu0001~u0005u000edsau0005tu001au000e~x3").length();
int char1 = 3;
int index = -1;
Label_0021: {
break Label_0021;
do {
char1 = s.charAt(index);
++index;
final String s2 = s;
final int beginIndex = index;
final char[] charArray = s2.substring(beginIndex, beginIndex + char1).toCharArray();
int length2;
int n3;
final int n2 = n3 = (length2 = charArray.length);
int n4 = 0;
while (true) {
Label_0184: {
if (n2 > 1) {
break Label_0184;
}
length2 = (n3 = n4);
do {
final char c3 = charArray[n3];
char c4 = '';
switch (n4 % 7) {
case 0: {
c4 = 'u0017';
break;
}
case 1: {
c4 = 'u0016';
break;
}
case 2: {
c4 = 'u0013';
break;
}
case 3: {
c4 = 's';
break;
}
case 4: {
c4 = 'u0011';
break;
}
case 5: {
c4 = 'h';
break;
}
default: {
c4 = '.';
break;
}
}
charArray[length2] = (char)(c3 ^ c4);
++n4;
} while (n2 == 0);
}
if (n2 > n4) {
continue;
}
break;
}
c2[n++] = new String(charArray).intern();
} while ((index += char1) < length);
}
c = c2;
}
}

当我尝试编译时，段中出现错误。由于无法访问的代码而出错，为什么会这样？

do {
char1 = s.charAt(index);
++index;
final String s2 = s;
final int beginIndex = index;
final char[] charArray = s2.substring(beginIndex, beginIndex + char1).toCharArray();
int length2;
int n3;
final int n2 = n3 = (length2 = charArray.length);
int n4 = 0;
while (true) {
Label_0184: {
if (n2 > 1) {
break Label_0184;
}
length2 = (n3 = n4);
do {
final char c3 = charArray[n3];
char c4 = '';
switch (n4 % 7) {
case 0: {
c4 = 'u0017';
break;
}
case 1: {
c4 = 'u0016';
break;
}
case 2: {
c4 = 'u0013';
break;
}
case 3: {
c4 = 's';
break;
}
case 4: {
c4 = 'u0011';
break;
}
case 5: {
c4 = 'h';
break;
}
default: {
c4 = '.';
break;
}
}
charArray[length2] = (char)(c3 ^ c4);
++n4;
} while (n2 == 0);
}
if (n2 > n4) {
continue;
}
break;
}
c2[n++] = new String(charArray).intern();
} while ((index += char1) < length);
}
c = c2;
}

我想知道为什么会出现像无法访问的代码这样的错误？

Answer 1

无法访问的代码意味着您在返回或抛出或中断语句之后编写了一些代码。

在这里，在"do"开始之前，您显然有这个：

Label_0021: {
break Label_0021;

执行流在此中断标签处结束。因此，无法访问 do 块。