我想做一个莫尔斯电码-英语双向翻译
import java.util.Scanner;
public class JavaProject {
public static void main(String[] args) {
// TODO Auto-generated method stub
char [] Eng = { 'a' ,'b' ,'c' ,'d' ,'e' ,'f' ,'g' ,'h' ,'i' ,'j' ,'k' ,'l' ,'m' ,'n' ,'o','p' ,'q' ,'r' ,'s' ,'t' ,'u' ,'v' ,'w' ,'x' ,'y' ,'z' };
String [] Code = { ".-" , "-..." , "-.-." , "-.." , "." , "..-." , "--." , "...." , ".." , ".---" , "-.-" , ".-.." , "--" , "-." , "---" , ".--." , "--.-" , ".-." , "..." , "-" , "..-" , "...-" , ".--" , "-..-" , "-.--" , "--.." , "|" };
System.out.println(" Enter Morse Code or something in English. A for english, or B for morse code.");
Scanner a = new Scanner(System.in);
String z = a.nextLine();
if (z.equals("A"));
{
System.out.println("enter in english");
Scanner f = new Scanner(System.in);
String b = f.nextLine();
for ( int x = 0; x < Eng.length; x++ )
{
for ( int y = 0; y < b.length (); y++ )
{
if ( Eng [ x ] == b.charAt ( y ) )
System.out.print ( Code [ x ] + " " );
}
}
}
else if (z.equals("B"));
{
System.out.println("enter in Morse");
Scanner v = new Scanner(System.in);
String n = v.nextLine();
for ( int i = 0; i < Code.length; i++ )
{
for ( int p = 0; p < n.length (); p++ )
{
if ( Eng [ i ] == n.charAt ( p ) )
System.out.print ( Eng [ i ] + " " );
}
}
}
}
}
英语到莫尔斯的翻译是完美的,但是else这个词会导致错误。
另外,我试着这样做,如果我输入"this",那么它将转到莫尔斯或英语翻译,但它似乎不起作用
由于某种原因,单词else导致错误
变化
if (z.equals("B"));
if (z.equals("A"));
if (z.equals("B"))
if (z.equals("A"))
这只是一个修复,使您的两个if块工作…但是你写逻辑的方式既不是English->Morse是正确的也不是more ->English是正确的
工作代码:
public static void main(String[] args) {
char[] Eng = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w',
'x', 'y', 'z' };
String[] Code = { ".-", "-...", "-.-.", "-..", ".", "..-.", "--.",
"....", "..", ".---", "-.-", ".-..", "--", "-.", "---", ".--.",
"--.-", ".-.", "...", "-", "..-", "...-", ".--", "-..-",
"-.--", "--..", "|" };
System.out.println("Enter your choice: n1. A for English -> Morse Code n2. B for Morse Code -> English");
Scanner a = new Scanner(System.in);
String z = a.nextLine();
if (z.equalsIgnoreCase("A")) {
System.out.println("enter in english");
String b = a.nextLine();
for (int x = 0; x < b.length(); x++) {
for (int y = 0; y < Eng.length; y++) {
if (Eng[y] == b.charAt(x))
System.out.print(Code[y] + " ");
}
}
}
else if (z.equalsIgnoreCase("B")) {
System.out.println("enter in Morse");
String n =a.nextLine();
String[] arr = n.split(" ");
for (int p = 0; p < arr.length; p++) {
for (int y = 0; y < Code.length; y++) {
if (Code[y].equals(arr[p]))
System.out.print(Eng[y]);
}
}
}
a.close();
}
提示…
- 不要像以前那样使用太多扫描仪…这一切都可以用一个扫描器完成。
- 总是关闭你的资源后使用…这些是java中的良好实践…
a) if后面的分号是错误的。
if (z.equals("A"));
表示不会执行任何操作。
b)您正在浏览英文字符,然后查看其中一个是否包含在输入中。错了。你必须遍历输入并查找相应的字符。你这样做,"sos"将被编码为"oss",因为它首先查找"o",找到它,然后查找"s",找到它,再找到它——因为"o"在英语字母表中是第一位的。
c)莫尔斯->英语不能这样工作,因为您不能查看单个莫尔斯字符。我建议将输入分割为"(String.split),然后将结果与Code数组进行比较,以找到正确的索引。目前,sos将被检查 ".", ".", ".", "-", ..."。"。但是您要检查的是"…","——","…",这将是"... --- ...".split(" ");
问题是,您只在代码段的more code处测试一个字符:
for ( int p = 0; p < n.length (); p++ )
{
if ( Eng [ i ] == n.charAt ( p ) )
System.out.print ( Eng [ i ] + " " );
}
要识别整个术语,请使用:
n.compareTo(Code[i]) == 0)
最终代码: public static void main(String[] args) {
char[] Eng = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w',
'x', 'y', 'z' };
String[] Code = { ".-", "-...", "-.-.", "-..", ".", "..-.", "--.",
"....", "..", ".---", "-.-", ".-..", "--", "-.", "---", ".--.",
"--.-", ".-.", "...", "-", "..-", "...-", ".--", "-..-",
"-.--", "--..", "|" };
System.out
.println(" Enter Morse Code or something in English. A for english, or B for morse code.");
Scanner a = new Scanner(System.in);
String z = a.nextLine();
if (z.equals("A")) {
System.out.println("enter in english");
Scanner f = new Scanner(System.in);
String b = f.nextLine();
for (int x = 0; x < Eng.length; x++) {
for (int y = 0; y < b.length(); y++) {
if (Eng[x] == b.charAt(y))
System.out.print(Code[x] + " ");
}
}
} else if (z.equals("B"))
{
System.out.println("enter in Morse");
Scanner v = new Scanner(System.in);
String n = v.nextLine();
for (int p = 0; p < Code.length; p++) {
if (n.compareTo(Code[p])==0){
System.out.print(Eng[p] + " ");
break;
}
}
}