PySide程序崩溃处理程序

Question

我的程序在遇到错误时会发送电子邮件。是否有一种方法来处理这个程序的崩溃和发送电子邮件关于它在这个程序?

Answer 1

您正在寻找sys.excepthook，这里有一个例子:

#!/usr/bin/env python
#-*- coding:utf-8 -*-
import cStringIO, traceback
from PyQt4 import QtGui, QtCore
errorNotice = """
An unhandled exception occurred. Details will be reported
via an automatic email.
"""
class MyMessageBox(QtGui.QMessageBox):
    def __init__(self, *args, **kwargs):            
        super(MyMessageBox, self).__init__(*args, **kwargs)
        self.tracebackInfoStream = cStringIO.StringIO()
        self.setIcon(QtGui.QMessageBox.Critical)
        self.finished.connect(self.on_finished)
    def getTraceback(self, exceptionTraceback):
        traceback.print_tb(
            exceptionTraceback,
            None,
            self.tracebackInfoStream
        )
        self.tracebackInfoStream.seek(0)
        return self.tracebackInfoStream.read()
    def exceptHook(self, exceptionType, exceptionValue, exceptionTraceback):   
        tracebackInfo = self.getTraceback(exceptionTraceback)
        self.setDetailedText(tracebackInfo)
        self.setText(errorNotice)
        self.exec_()
    @QtCore.pyqtSlot()
    def on_finished(self):  
        QtGui.QApplication.quit()
class MyWindow(QtGui.QWidget):
    def __init__(self, parent=None):
        super(MyWindow, self).__init__(parent)
        self.pushButtonError = QtGui.QPushButton(self)
        self.pushButtonError.setText("Raise an Error!")
        self.pushButtonError.clicked.connect(self.on_pushButtonError_clicked)
        self.layoutVertical = QtGui.QVBoxLayout(self)
        self.layoutVertical.addWidget(self.pushButtonError)
    @QtCore.pyqtSlot()
    def on_pushButtonError_clicked(self):
        raise UserWarning("This is an error")
if __name__ == "__main__":
    import sys
    app = QtGui.QApplication(sys.argv)
    app.setApplicationName('MyWindow')
    myMessageBox = MyMessageBox()
    sys.excepthook = myMessageBox.exceptHook
    main = MyWindow()
    main.show()
    sys.exit(app.exec_())