好吧,我有一个看起来像的数组。
[0] => Array (
first_name => j,
last_name => b,
times => Array(
[0] => Array(
[in1] => a date here
[out1] => a date here
[in2] => a date here
[out2] => a date here
)
[1] => Array(
[in1] => another date here
[out1] => another date here
[in2] => another date here
[out2] => another date here
)))
为了 SO 布局,我简化了数组的外观......
这个列表通常会在开始数组中有超过 100 个不同的人,这些人都需要输出到浏览器...... 这很好,我可以做到..
{% for entity in entity %}
<h3>{{ entity.first_name }} {{ entity.last_name }} ( {{ start|date("m/d/Y") }} - {{ end|date("m/d/Y")}} )</h3>
<table = border="1" cellpadding="5" cellspacing="0">
<thead>
<tr>
<th>Date</th>
<th>In</th>
<th>Lunch Out</th>
<th>Lunch In</th>
<th>Out</th>
<th>Extra In</th>
<th>Extra Out</th>
<th>Total Time</th>
</tr>
</thead>
<tbody>
{% for times in entity.times %}
<tr>
<td>{{ entity.times.daydate|date("M jS Y") }} </td>
<td>{{ entity.times.in1 is empty ? "" : entity.times.in1|date("h:i A") }}</td>
<td>{{ entity.times.out1 is empty ? "" : entity.times.out1|date("h:i A") }}</td>
<td>{{ entity.times.in2 is empty ? "" : entity.times.in2|date("h:i A") }}</td>
<td>{{ entity.times.out2 is empty ? "" : entity.times.out2|date("h:i A") }}</td>
<td>{{ entity.times.in3 is empty ? "" : entity.times.in3|date("h:i A") }}</td>
<td>{{ entity.times.out3 is empty ? "" : entity.times.out3|date("h:i A") }}</td>
<td>{{ entity.times.totaltime }} Hours</td>
</tr>
{% endfor%}
</tbody>
</table>
{% endfor %}
那是我目前的树枝代码... 我需要帮助的是,因为每个"实体"都有一个 .times 子数组,也需要循环访问。 正确的方法是什么?
{% for entity in entities %}
<h3>{{ entity.foo }}</h3>
{% for time in entity.times %}
<p>{{ time.bar }}</p>
{% endfor %}
{% endfor %}
我简化了代码,以便更容易看到您正在寻找的概念。