如何在springsecurity中添加@security注释

Question

如何在控制器的方法中添加@Secure annatation并使其运行？现在，当我运行它时，它得到了一个异常，比如：

org.springframework.beans.factory.BeanCreationException：创建文件[C:\workspace\sts\springsource\vfabric-tc-server-developer-2.2.6.1中定义的名称为"companyController"的bean时出错。RELEASE\spring insight instance\wtpwebapps\BillingEngine\WEB-INF\classes\sesami\common\management\WEB\controller\companyController.class]：bean初始化失败；嵌套异常为org.springframework.aop.framework.AopConfigException：意外的aop异常；嵌套异常为org.springframework.beans.factory.BeanCreationException：创建名为"org.springfframework.security.access.entercept.aopalliance.MethodSecurityInterceptor#0"的bean时出错：在设置bean属性"accessDecisionManager"时无法解析对bean"accessDecision Manager"的引用；嵌套异常为org.springframework.beans.factory.NoSuchBeanDefinitionException：未定义名为"accessDecisionManager"的beanorg.apache.catalina.core.StandardContext.listenerStart（StandardContext.java:4723）网址：org.apache.catalina.core.StandardContext$1.call（StandardContext.java位于java.lang.Thread.run（未知源）由：org.springframework.aop.framework.AopConfigException引起：意外的aop异常；嵌套异常为org.springframework.beans.factory.BeanCreationException：创建名为"org.springfframework.security.access.entercept.aopalliance.MethodSecurityInterceptor#0"的bean时出错：在设置bean属性"accessDecisionManager"时无法解析对bean"accessDecision Manager"的引用；嵌套异常位于。。。19个

我有spring-security.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns:context="http://www.springframework.org/schema/context"
    xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/security
        http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<global-method-security secured-annotations="enabled">
<!-- 
<protect-pointcut access="ROLE_ADMIN"
        expression="execution(* com.sesami.common.management.web.controller.AdminController.*(..))" />
         -->
</global-method-security>
<!-- URL pattern based security -->
<http auto-config="false" entry-point-ref="authenticationEntryPoint"
    use-expressions="true">
    <custom-filter ref="authenticationFilter" position="FORM_LOGIN_FILTER" />
    <intercept-url access="hasRole('ROLE_ADMIN')" pattern="/common/admin/**" />
    <intercept-url pattern="/common/accounting/**" access="hasRole('ROLE_USER')" />
    <intercept-url pattern="/common/billing/**" access="hasRole('ROLE_COMPANY')" />
    <logout logout-success-url="/" logout-url="/logout"/>
</http>.........

在控制器中，我像这样添加

@Secure("ROLE_ADMIN")
@RequestMapping(value = "/common/admin/addAdmin", method = RequestMethod.GET)
    public String add(ModelMap map) {
        map.addAttribute(new Administrator());
        return "/common/admin/addAdmin";
    }

我需要配置或导入一些类吗？

Answer 1

Cannot resolve reference to bean 'accessDecisionManager' while setting bean property 'accessDecisionManager'; nested exception is
org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'accessDecisionManager' is defined 

Spring应该为您创建一个默认的accessDecisionManager，但这似乎没有发生，可能是由于一些配置问题。如果您在http配置中将auto-config设置为true，会发生什么？

Answer 2

<bean id="accessDecisionManager" class="org.springframework.security.access.vote.UnanimousBased" xmlns="http://www.springframework.org/schema/beans">
    <constructor-arg>
        <list>
            <bean class="org.springframework.security.oauth2.provider.vote.ScopeVoter" />
            <bean class="org.springframework.security.access.vote.RoleVoter" />
            <bean class="org.springframework.security.access.vote.AuthenticatedVoter" />
        </list>
    </constructor-arg>
</bean>

您必须定义这个bean。