苹果TVOS应用程序调用另一个TVOS应用

Question

我已经编写了一个显示视频库的TVOS应用程序，这很好，但是，我需要能够调用我从另一个TVOS应用创建的这个TVOS应用。我不知道该怎么做，也不知道这是否可能。基本上，我想要一个底部可能有一个按钮的TVOS应用程序，当你点击它时，另一个TVOS应用将被动态加载。另一种想法是，我希望父应用程序成为子应用程序的容器——父应用程序除了如何加载外，对子应用程序一无所知。

有什么帮助吗？下面是我的代码。

---

应用程序#2（由应用程序#1打开）：

info.plist:

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>brightline123456</string>
</array>

AppDelegate.swift：

@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate, TVApplicationControllerDelegate {
var window: UIWindow?
var appController: TVApplicationController?
static let TVBaseURL = "http://localhost:9001/"
static let TVBootURL = "(AppDelegate.TVBaseURL)js/application.js"
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
    window = UIWindow(frame: UIScreen.mainScreen().bounds)
    // 1
    let appControllerContext = TVApplicationControllerContext()
    // 2
    guard let javaScriptURL = NSURL(string: AppDelegate.TVBootURL) else {
        fatalError("unable to create NSURL")
    }
    appControllerContext.javaScriptApplicationURL = javaScriptURL
    appControllerContext.launchOptions["BASEURL"] = AppDelegate.TVBaseURL
    // 3
    appController = TVApplicationController(context: appControllerContext, window: window, delegate: self)
    return true
  }
}

Application.js:

var resourceLoader;
App.onLaunch = function(options) {
// 2
var javascriptFiles = [
`${options.BASEURL}js/ResourceLoader.js`,
`${options.BASEURL}js/Presenter.js`
];
evaluateScripts(javascriptFiles, function(success) {
if(success) {
  // 3
  resourceLoader = new ResourceLoader(options.BASEURL);
   resourceLoader.loadResource(`${options.BASEURL}templates/RWDevConTemplate.xml.js`, function(resource) {
    var doc = Presenter.makeDocument(resource);
    doc.addEventListener("select", Presenter.load.bind(Presenter)); //add this line
    Presenter.pushDocument(doc);
  });
} else {
  var errorDoc = createAlert("Evaluate Scripts Error", "Error attempting to evaluate external JavaScript files.");
  navigationDocument.presentModal(errorDoc);
}
});
}

---

应用程序#1（将使用canOpenUrl打开应用程序#2）：

info.plist:

<key>CFBundleURLTypes</key>
<array>
    <dict>
        <key>CFBundleURLSchemes</key>
        <array>
            <string>brightline123456</string>
        </array>
        <key>CFBundleTypeRole</key>
        <string></string>
        <key>CFBundleURLName</key>
        <string>com.brightline123456</string>
    </dict>
</array>

AppDelegate.swift：

import UIKit
@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {
var window: UIWindow?

func application(application: UIApplication, openURL:(NSURL), sourceApplication:(NSString), didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
    let url  = NSURL(string: "brightline123456://"); // Change the URL with your URL Scheme
    if UIApplication.sharedApplication().canOpenURL(url!) == true
    {
        UIApplication.sharedApplication().openURL(url!)
    }
    // Override point for customization after application launch.
    window = UIWindow(frame: UIScreen.mainScreen().bounds)
    return true
}

}

Answer 1

查看另一篇文章https://forums.developer.apple.com/message/7973#7973你的不应该

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>brightline123456</string>
</array>

是否在呼叫方应用程序中（在您的情况下为App1）？